获取php中父类的所有定义的类 [英] Get all defined classes of a parent class in php

问题描述

  class foo我需要确定所有文件都包含后， {
} 
 class boo extends foo {
} 
 class bar extends foo {
} 
  

我想要获取一个数组：

  array（'boo'，'bar'）; 
  

解决方案

如果你需要的话， ，基类不应该知道这一点。

然而，如果你的定义已经包括（即你不需要包括新文件类，你可能你可以运行：

  $ children = array（）; 
 foreach（get_declared_classes（）as $ class）{
 if（$ class instanceof foo）$ children [] = $ class; 
} 
  

I need to determine, after all files have been included, which classes extend a parent class, so:

class foo{
}
class boo extends foo{
}
class bar extends foo{
}

and I'd like to be able to grab an array like:

array('boo','bar');

解决方案

If you need that, it really smells like bad code, the base class shouldn't need to know this.

However, if you definitions have been included (i.e. you don't need to include new files with classes you possibly have), you could run:

$children  = array();
foreach(get_declared_classes() as $class){
    if($class instanceof foo) $children[] = $class;
}

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