调用类方法（使用构造函数）在php中没有对象实例化 [英] calling class method (with constructors) without object instantiation in php

问题描述

Ive看了看，试过，但我找不到答案。

Ive looked and tried but I can't find an answer.

在PHP中，是否可以调用类的成员函数（当该类需要一个构造函数来接收参数时）而不将其实例化为一个对象？

In PHP, is it possible to call a class' member function (when that class requires a constructor to receive parameters) without instantiating it as an object?

代码示例（给出错误）：

A code example (which gives errors):

<?php

class Test {
    private $end="";

    function __construct($value) {
        $this->end=$value;
    }

    public function alert($value) {
        echo $value." ".$this->end;
    }
}

//this works:
$example=new Test("world");
$example->alert("hello");

//this does not work:
echo Test("world")::alert("hello");

?>

推荐答案

不幸的是PHP不支持这样做，但你是一个有创意的人：D

Unfortunately PHP doesn't have support to do this, but you are a creative and look guy :D

你可以使用工厂，样例：

You can use an "factory", sample:

<?php

class Foo
{
   private $__aaa = null;

   public function __construct($aaa)
   {
      $this->__aaa = $aaa;
   }

   public static function factory($aaa)
   {
      return new Foo($aaa);
   }

   public function doX()
   {
      return $this->__aaa * 2;
   }
}

Foo::factory(10)->doX();   // outputs 20

这篇关于调用类方法（使用构造函数）在php中没有对象实例化的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！