C ++使用带方括号的指针指向实例 [英] C++ using square brackets with pointer to instance
问题描述
我创建了一个单例类,它使用 GetInstance()
方法来获取实例地址(指针)。
在类中我有一个unsigned long int数组,我创建了 operator []
(直接访问数组)。
我如何使用从 GetInstance
获得的指针以使用 []运算符
?
我尝试过:
class risc {// singleton
protected:
unsigned长寄存器[8];
static risc * _instance;
risc(){
for(int i = 0; i <8; i ++){
registers [i] = 0;};
}
public:
unsigned long operator [](int i)const {return registers [i];}; // get []
unsigned long& operator [](int i){return registers [i];}; // set []
static risc * getInstance(){// constructor
if(_instance == NULL){
_instance = new risc();
}
return _instance;
}
};
risc * Risc = getInstance();
* Risc [X] = ...
。
试试这个:
方括号运算符优先于指针解引用运算符。也可以通过名称调用操作符,虽然这会导致一个相当拙劣的语法:
Risc-> ](x)= ...
I've created a singleton class which uses GetInstance()
method to get the instance address (pointer).
Inside the class i have an array of unsigned long int which i've created the operator []
for it (direct access to the array).
How can i use the pointer i got from GetInstance
in order to use the [] operator
?
I've tried :
class risc { // singleton
protected:
unsigned long registers[8];
static risc* _instance;
risc() {
for (int i=0;i<8;i++) {
registers[i]=0;};
}
public:
unsigned long operator [](int i) const {return registers[i];}; // get []
unsigned long & operator [](int i) {return registers[i];}; // set []
static risc* getInstance() { // constructor
if (_instance==NULL) {
_instance=new risc();
}
return _instance;
}
};
risc* Risc=getInstance();
*Risc[X]=...
But it doesn't work ... is there a way i can use the brackets to access the array directly using the class pointer ?
Thanks !
Try this:
(*Risc)[X]=...
The square brackets operator takes precedence over the pointer dereference operator. It is also possible to call the operator by name, although this results in a rather clunky syntax:
Risc->operator[](x) = ...
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