为什么我不能将一个类划分为多个文件 [英] Why I can't divide a class over several files

问题描述

我试图创建一个 TestClass 分成几个文件。我已经拆分了3个文件，其中第一个文件 TestClassPart1.php 有类的开始 class TestClass {最后一个文件 TestClassPart3.php 有类的结束括号。这些是3个文件

  // TestClassPart1.php 
<？php 
 class TestClass {
 public function func1（）{
 echofunc 1; 
} 
 
 //TestClassPart2.php 
<？php 
 public function func2（）{echofunc 2; } 
 
 //TestClassPart3.php 
<？php 
 public function func3（）{echofunc 3; } 
 
} 
  

然后我在实际的类文件c $ c> TestClass.php 所以TestClass.php只是所有3个文件的粘合。

 <？php 
 require'TestClassPart1.php'; 
 require'TestClassPart2.php'; 
 require'TestClassPart3.php'; 
  

我认为这应该可以工作，但是当我尝试创建一个 TestClass 并调用其中一个函数，我得到 parse错误，期待T_FUNCTION'在C：\wamp\www\TestClassPart1.php第5行。第5行是 func1（）

<$ p的 $ p> <？php
require'TestClass.php';
$ nc = new TestClass（）？
$ nc-> func1（）;


这应该不行吗？我想你可以传播一个类在几个文件没有问题。

解决方案

当您 require

您的类不完整，所以当PHP解析

class TestClass {
public function func1（）{
echofunc 1;
}


它不能理解类，因为关闭}

并预期你的下一个问题。这

  class Foo 
 {
 include'methods.php'
} 
  

也不起作用。

---

从 PHP手册在OOP 4 （无法在5中找到）

转换为多个文件。你也不能将类定义分成多个PHP块，除非断点在方法声明内。以下不工作：

 <？php 
 class test {
？> 
 <？php 
 function test（）{
 print'OK'; 
} 
} 
？> 
  

但是，以下是允许的：

 <？php 
 class test {
 function test（）{
？ > 
<？php 
 print'OK'; 
} 
} 
？> 
  

---

如果您正在查找水平重用，请等待PHP.next，包括Traits 或查看

• 我可以将代码包含到PHP类中？

I'm trying to create a class TestClass that's divided over several files. I have split it over 3 files where the first file TestClassPart1.php has the start of the class class TestClass { and the last file TestClassPart3.php has the closing bracket of the class. These are the 3 files

//TestClassPart1.php
<?php  
class TestClass {    
   public function func1(){ 
      echo "func 1"; 
   }

//TestClassPart2.php
<?php    
   public function func2(){ echo "func 2"; }

//TestClassPart3.php
<?php    
   public function func3(){ echo "func 3"; }

}

I then recombine in the actual class file called TestClass.phpso TestClass.php is just the glue of all 3 files.

<?php
require 'TestClassPart1.php';
require 'TestClassPart2.php';
require 'TestClassPart3.php';

I thought this should work, but when I try to create an instance of TestClass and call one of the functions, I get parse error, expecting T_FUNCTION' in C:\wamp\www\TestClassPart1.php on line 5. Line 5 is the } of func1()

<?php
require 'TestClass.php';
$nc = new TestClass();
$nc->func1();

Shouldn't this work? I thought you could spread a class over several files no problem. Am I doing it wrong?

解决方案

When you require a file, PHP will parse and evaluate the contents.

You class is incomplete, so when PHP parses

class TestClass {    
   public function func1(){ 
      echo "func 1"; 
   }

it's not able to make sense of the class, because the closing } is missing.

Simple as that.

---

And to anticipate your next question. This

class Foo
{
    include 'methods.php'
}

will not work either.

---

From the PHP Manual on OOP 4 (couldnt find it in 5)

You can NOT break up a class definition into multiple files. You also can NOT break a class definition into multiple PHP blocks, unless the break is within a method declaration. The following will not work:

<?php
class test {
?>
<?php
    function test() {
        print 'OK';
    }
}
?>

However, the following is allowed:

<?php
class test {
    function test() {
        ?>
        <?php
        print 'OK';
    }
}
?>

---

If you are looking for Horizontal Reuse, either wait for PHP.next, which will include Traits or have a look at

• Can I include code into a PHP class?

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