为什么我不能从两个ints返回一个double被划分 [英] Why can't I return a double from two ints being divided

问题描述

相对较新的编码，并有一个关于基本划分的问题。如何来到以下不返回答案我认为它会：

Relatively new to coding and have an issue regarding basic division. How come to following doesn't return the answer I thought it would:

int a=7;
int b=3;
double c=0;
c=a/b;

我会把钱放在2.3333的结果上，但它只返回2.如果A和B然后重新分配到双倍的答案确实转向2.333。但是肯定是因为C已经是双重的了，它应该工作了吗？

I would have put money on the result being 2.3333, however it only returns 2. If A and B are then reassigned to being doubles the answer does turn to 2.333. But surely because C is already a double it should have worked?

int / int = double不起作用？

How come int/int=double doesn't work? Maybe an odd question but it's puzzled me.

推荐答案

这是因为您使用的整数除法版本 operator / ，它需要2 int s并返回 int 。为了使用 double 版本，它返回 double ，至少有一个 int 必须显式地转换为 double 。

This is because you are using the integer division version of operator/, which takes 2 ints and returns an int. In order to use the double version, which returns a double, at least one of the ints must be explicitly casted to a double.

c = a/(double)b;

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