julia：OOP [英] julia: OOP or not

问题描述

我正在与Julia合作Juno。

I'm working on Juno with Julia.

我不知道Julia是否支持OOP。

I don't know if Julia suports OOP or not.

例如，是否有类似 class 或 struct 的c ++？ br>

For example, is there something like class or struct of c++?

如何用数据或函数等成员声明它？

How to declare it with members such as a data or a function?

推荐答案

如有疑问，请阅读文档...

When in doubt, read the documentation...

http://docs.julialang.org/en/release-0.4/manual/types/#composite-types

长故事：

type MyType
    a::Int64
    b::Float64
end

x = MyType(3, 4)

x.a

EDIT：方法定义在类型定义之外，例如

Methods are defined outside the type definition, e.g.

function double(x::MyType)
    x.a *= 2
end

方法do 不是住在类型中，例如，他们会在C ++或Python中做。这允许Julia的一个关键特性，即多重分派，也与用户定义的类型一起工作，这些类型与系统定义的类型完全相同。

Methods do not live inside the type, as they would do in C++ or Python, for example. This allows one of the key feature of Julia, multiple dispatch, to work also with user-defined types, which are on exactly the same level as system-defined types.

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