在批处理脚本中从字符串中提取前导数字 [英] Extract leading numbers from a string in batch script

问题描述

我是批量脚本的新手。虽然我有这个问题的shell和python解决方案，但陷入批处理脚本。

I am new to batch scripting. although i have shell and python solutions for this problem but got stuck in batch script.

我有字符串 123_happy ， 234.healthy ， 3456wealthy 等。

想从每个字符串中提取前导数字。

I want to extract the leading numbers from each string. the only pattern here is that all these strings contain numbers in the beginning.

我不能使用echo ％str：〜0,3％ ，因为它不符合我的要求。

I can't use echo %str:~0,3% as it doesn't fulfill my requirement.

推荐答案

循环（1 => 1000应该就足够了）对变量的字符，找到第一个字符不在数字范围。提取之前的子字符串：

Loop (1=>1000 should be enough ;)) on the characters of the variable and find the first char not in number range. Extract the substring before:

@echo off

set z=123_happy
setlocal enabledelayedexpansion
set result=

for /L %%i in (0,1,1000) do (
set zz=!z:~%%i,1!
if x!zz!==x exit /b
if !zz! lss 0  (
set result=!z:~,%%i!
goto out
)
if !zz! gtr 9  (
set result=!z:~,%%i!
goto out
)
)
:out
echo result=!result!

结果：

result=123

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