在Swift中重新初始化一个延迟初始化的变量 [英] Re-initialize a lazy initialized variable in Swift

问题描述

我有一个变量初始化为：

I have a variable that initialized as:

lazy var aClient:Clinet = {
    var _aClient = Clinet(ClinetSession.shared())
    _aClient.delegate = self
    return _aClient
}()

$ b b

问题是，在某些时候，我需要重置这个 aClient 变量，以便当 ClinetSession .shared（）更改。但是如果我将类设置为可选 Clinet？，当我尝试将其设置为 nil 。如果我只是在代码中使用 aClient = Clinet（ClinetSession.shared（））重置它，它将最终以 EXEC_BAD_ACCESS 。

The problem is, at some point, I need to reset this aClient variable so it can initialize again when the ClinetSession.shared() changed. But if I set the class to optional Clinet?, LLVM will give me an error when I try to set it to nil. If I just reset it somewhere in the code using aClient = Clinet(ClinetSession.shared()), it will end up with EXEC_BAD_ACCESS.

有没有办法可以使用 lazy 并允许重置本身？

Is there a way that can use lazy and being allowed to reset itself?

谢谢！

推荐答案

lazy是一次性初始化。您要采用的模型可能只是一个按需初始化模型：

lazy is explicitly for one-time only initialization. The model you want to adopt is probably just an initialize-on-demand model:

var aClient:Client {
    get {
        if(_aClient == nil) {
            _aClient = Client(ClientSession.shared())
        }
        return _aClient!
    }
}

var _aClient:Client?

现在每当 _aClient c> nil ，它将被初始化并返回。可以通过设置 _aClient = nil

Now whenever _aClient is nil, it will be initialized and returned. It can be reinitialized by setting _aClient = nil

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