OSX - 禁用Webview的外部站点链接 [英] OSX - Disable External Site Linking for Webview

问题描述

我正在查看WebView中的本地html页面，如果用户点击页面中的任何按钮即< a href =www，我想禁用去任何外部网站。 google.com> c>

I'm working to view a local html page inside a WebView and I want to disable going to any external website if the user clicks any button within the page i.e. <a href="www.google.com">

推荐答案

您要设置 policyDelegate 为您的视图。请参阅 WebPolicyDelegate 的文档。您要实现的具体方法是：

You want to set a policyDelegate for your view. See the docs for WebPolicyDelegate. The specific method you want to implement is:

- (void)webView:(WebView *)webView decidePolicyForNavigationAction:(NSDictionary *)actionInformation 
                                   request:(NSURLRequest *)request
                                   frame:(WebFrame *)frame
                                   decisionListener:(id<WebPolicyDecisionListener>)listener

最简单的事情就是调用 [listener ignore] 。这也将防止任何后退/前进导航，重新加载或表单提交工作。如果你想要更多的控制，你可以看看 actionInformation 字典，并检查类型之前调用 [listener ignore] [listener use] 。

The simplest thing to do is just call [listener ignore] for everything. That will also prevent any back/forward navigation, reloads, or form submits from working. If you want more control, you can look at the actionInformation dictionary and check the type before calling [listener ignore] or [listener use].

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