禁用Android WebView中的链接 [英] Disabling links in android WebView

问题描述

首先，我在编程的世界很绿，所以原谅我，如果我的问题在任何部分缺乏通关。
我目前正试图制作一个需要链接的应用程序无法在WebView中执行，或者在另一个浏览器中执行链接。我设法放了以下两个链接：在Android Webview中，我是否可以修改网页的DOM？和 Titanium Appcelerator Quickie：禁用Webview中的链接，并创建以下工作代码：

  private class WebClient extends WebViewClient {
 @Override 
 public boolean shouldOverrideUrlLoading（WebView view，String url）{
 view.loadUrl（url）; 
返回true; 
} 
 
 @Override 
 public void onPageFinished（WebView视图，String url）
 {
 view.loadUrl（javascript：document.body.innerHTML = document.body.innerHTML.replace（/< a。* href = / gi，'< a href = \＃\_url ='）;）; 
} 
} 
  

上面的代码片段放在onCreate方法之前，在onCreate方法中被引用，如下所示：

  viewer =（WebView）findViewById（R.id.wv_engine）; 
 viewer.setWebViewClient（new WebViewClient（））; 
 viewer.loadUrl（content）; 
  

现在，代码工作...但只有在请求的网页被加载了第二次之后。我第一次执行WebView，example.com的所有链接都是完整的，可点击的和可执行的。使用反向按钮，退出WebView并重新输入它将通过更改

 < a href =http： //www.example.com\">link</a> 
  

至

 < a href =＃_url =http://www.example.com> link< / a> 
  

现在，我是一个不能确定的理论（我不是程序员）。我相信JavaScript被执行缓慢，这导致链接操纵永远不会发生。这就是为什么它第二次工作，而不是使用缓存。我从阅读这个讨论中得到了这些想法。但是我不知道如何纠正它。

所以我的问题是：如何确保显示的网站的任何链接都不能被使用？有没有办法在网站显示之前进行操作？

感谢您的时间和精力。这是真正的一个惊人的社区;）

• Krede

解决方案

我认为这是错误的：

  viewer.setWebViewClient（new WebViewClient （））; 
  

我想你的意思是：

  viewer.setWebViewClient（new WebClient（））; 
  

这解释了为什么在第一次加载时不禁用网址。但是我不明白为什么他们第二次被禁用。

此外，我想你应该删除这个：

  view.loadUrl（URL）; 
  

First, I am quite green in the world of programming, so forgive me if my question lacks clearance in any part. I am currently trying to make an app which requires links cannot be executed in the WebView - or in another browser for that sake. I have managed to put the following two links, In Android Webview, am I able to modify a webpage's DOM? and Titanium Appcelerator Quickie: Disable links in Webview, together and create the following working code:

private class WebClient extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        view.loadUrl(url);
        return true;
    }

    @Override
    public void onPageFinished(WebView view, String url) 
    {       
        view.loadUrl("javascript:document.body.innerHTML = document.body.innerHTML.replace(/<a.*href=/gi,'<a href=\"#\" _url=');");       
    }
}

The snippet above is placed before the onCreate-method and is referenced in the onCreate-method like this:

    viewer = (WebView) findViewById(R.id.wv_engine);
    viewer.setWebViewClient(new WebViewClient());
    viewer.loadUrl(content);

Now, the code works... But only after the requested webpage has been loaded a second time. The first time I execute the WebView, example.com has all its links intact, clickable and executedable. Using the backbutton, exiting the WebView and entering it again renders all the links disabled by changing

<a href="http://www.example.com">link</a>

to

<a href="#" _url="http://www.example.com">link</a>

Now, I a theory which I am not at all sure about (I am no programmer). I believe the JavaScript is executed to slow, which results in the links-manipulation never happening. That is why it works the second time working instead with with cache. I got those thought from reading this discussion. However I have no idea how to correct it.

So my question goes: How can I make sure that none of the links of the displayed website can ever be used? Is there a way to make manipulation happen before the site is displayed?

Thanks for your time and effort. This is truly an amazing community ;)

• Krede

解决方案

I think this is wrong:

viewer.setWebViewClient(new WebViewClient());

I guess you mean this instead:

viewer.setWebViewClient(new WebClient());

This explains why urls are not disabled at 1st load. But I don't understand why they are disabled 2nd time.

Additionally, I think you should remove this:

view.loadUrl(url);

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