排序Java集合 [英] Sort Java Collection
本文介绍了排序Java集合的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个Java集合:
集合< CustomObject> list = new ArrayList< CustomObject>();
CustomObject
有 id
解决方案
使用比较器:
List< CustomObject> list = new ArrayList< CustomObject>();
Comparator< CustomObject> comparator = new Comparator< CustomObject>(){
@Override
public int compare(CustomObject left,CustomObject right){
return left.getId() - right.getId(); // use your logic
}
};
Collections.sort(list,comparator); //使用比较器尽可能多的想要
System.out.println(list);
此外,如果 CustomObject
implements Comparable
,则只需使用 Collections.sort(list)
JDK 8的语法更简单。
List< CustomObject> list = new ArrayList< CustomObject>();
Collections.sort(list,(left,right) - > left.getId() - right.getId());
System.out.println(list);
更简单
List< CustomObject> list = new ArrayList<>();
list.sort((left,right) - > left.getId() - right.getId());
System.out.println(list);
显然,初始代码也可用于JDK 8。
I have a Java collection:
Collection<CustomObject> list = new ArrayList<CustomObject>();
CustomObject
has an id
field now before display list I want to sort this collection by that id
.
Is there any way I could that do that?
解决方案
Use a Comparator:
List<CustomObject> list = new ArrayList<CustomObject>();
Comparator<CustomObject> comparator = new Comparator<CustomObject>() {
@Override
public int compare(CustomObject left, CustomObject right) {
return left.getId() - right.getId(); // use your logic
}
};
Collections.sort(list, comparator); // use the comparator as much as u want
System.out.println(list);
Additionally, if CustomObject
implements Comparable
, then just use Collections.sort(list)
With JDK 8 the syntax is much simpler.
List<CustomObject> list = new ArrayList<CustomObject>();
Collections.sort(list, (left, right) -> left.getId() - right.getId());
System.out.println(list);
Much simplier
List<CustomObject> list = new ArrayList<>();
list.sort((left, right) -> left.getId() - right.getId());
System.out.println(list);
Obviously the initial code can be used for JDK 8 too.
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