如何从向量中删除元素？ [英] How do I remove an element from a Vector?

问题描述

这是我现在正在做的：

  private var accounts = Vector.empty [Account] 
 
 def removeAccount（account：Account）
 {
 accounts = accounts.filterNot（_ == account）
} 
  

有更可读的解决方案吗？理想情况下，我想写 accounts = accounts.remove（account）。

解决方案

我会用这个：

  accounts filterNot account == 
  

这对我来说很好，但是ymmv。我也想要一个计数不采取谓词，但集合库真的缺乏专门的方法，其中一个谓词可以推广操作。 p>

直到2.8.x，是 - 方法，因为语义问题。它可以真的回来了2.10如果我的记忆正在为我服务，但它没有。 修改：我检查了它，发现 - 现在保留为可修改应用。我会赞成 - ： / ： - 虽然在序列上，第一个或最后一个元素等于某事。任何人都愿意为此买票？我会upvote它。 ： - ）

This is what I'm doing now:

  private var accounts = Vector.empty[Account]

  def removeAccount(account: Account)
  {
    accounts = accounts.filterNot(_ == account)
  }

Is there a more readable solution? Ideally, I'd like to write accounts = accounts.remove(account).

解决方案

I'd use this:

accounts filterNot account.==

Which reads pretty well to me, but ymmv. I'd also like a count that doesn't take a predicate, but the collection library is really lacking in specialized methods where one with a predicate can generalize the operation.

Until 2.8.x, there was a - method, which got deprecated, iirc, because of semantic issues. It could actually have come back on 2.10 if my memory is serving me right, but it didn't. Edit: I checked it out, and saw that - is now reserved for a mutable method that modifies the collection it is applied on. I'd be all in favor of -:/:- though on sequences, where it makes sense to drop the first or last element equal to something. Anyone willing to front a ticket for that? I'd upvote it. :-)

这篇关于如何从向量中删除元素？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！