使用ImageMagick删除图像中除黑色以外的所有颜色？ [英] Using ImageMagick to remove all color except black in an image?

问题描述

情况是：我有许多来自扫描的文档图像。我想保留文档的主要内容 - 它是打印为黑色（＃000000周围的小范围的颜色）。但是，你知道，文件总是充满颜色：邮票，背景，装饰品，标志...等。

The situation is : I have many images of documents from scanning. I want to keep the document's main content - which is printed in color black (a small range of colors around #000000). But, you know, the documents are always full of colors : stamp, background, decorations, logos...etc.

我只想保留TEXTS

I just want to keep the TEXTS ONLY which were printed in the color black.

我尝试过 ImageMagick 到目前为止这个命令：

I've tried with ImageMagick and this command so far:

convert X.png -matte (+clone -fuzz 20% -transparent "#000000") -compose DstOut -composite X1.png

但结果不是预期的，文本是非常破坏，我不能读。
有人建议我将模糊度提高到70％：

But the result was not as expected , the text was very damaged that I cannot read. Someone suggested me to increase the fuzz to 70%:

convert X.png -matte (+clone -fuzz 70% -transparent "#000000") -compose DstOut -composite X1.png

更可读，但其他颜色保持太多。

Then the text appeared to be more readable, but the other colors kept remaining too.

你能给我一个更好的解决方案，我的情况吗？

Can you please show me a better solution for my situation? Every suggestion would be highly appreciated!

推荐答案

要匹配除黑色之外的所有颜色，您可以使用 + opaque＃000000。

为了包括＃000000左右的范围，你可以尝试不同的百分比 fuzz 运算符：

In order to include a little range around #000000 you can try different percentages with the fuzz operator:

convert input.png -fill white -fuzz 10% +opaque "#000000" result.png

使用ImageMagick 6.6.0-1在Windows上

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