运行节点bin脚本时确定命令行工作目录 [英] Determine command line working directory when running node bin script

问题描述

我正在创建一个节点命令行界面。它是全局安装的，并使用bin文件来执行。

我打算在我正在工作的文件的根目录下打开一个命令窗口，然后运行该命令，但是我一直无法确定当前工作目录为 process.cwd（）正在返回节点包的目录。我最初假设，因为代码是使用批处理文件作为包装器（这就是如何bin文件可以执行没有节点在开始），那么这是不可能的，但是咖啡脚本设法做到。我看了一下咖啡脚本源代码，但不能跟随它（没有足够的经验）。

要测试它自己创建一个包package.json file：

  {
name：test-package，
version： 1.0.0，
bin：{
test-package：./bin/test-package
}，
main：/ lib / test
} 
  

此测试包文件在bin：

 ＃！/ usr / bin / env node 
 
 var path = require（'path'）; 
 var fs = require（'fs'）; 
 var lib = path.join（path.dirname（fs.realpathSync（__ filename）），'../lib'）; 
 
 require（lib +'/ test'）; 
  

任何人都可以为此留出一些光。

，然后尝试在lib / test中获取命令行目录。

解决方案

• process.cwd（）如果应用程序中没有被'process.chdir'更改，则返回已执行命令的目录（不是节点程序包的目录）。


• __ filename 返回文件的绝对路径。


• __ dirname 返回 __ filename 目录的绝对路径。

如果您需要从您的模块目录加载文件，您需要使用相对路径。

  require（'../ lib /测试'）; 
  

而不是

 code> var lib = path.join（path.dirname（fs.realpathSync（__ filename）），'../lib'）; 
 
 require（lib +'/ test'）; 
  

它总是相对于文件调用，而不依赖于当前工作目录。 p>

I am creating a node command line interface. It is installed globally and uses a bin file to execute.

I plan to have a command window open at the root directory of the files I am working on and then just run the command however I have been unable to determine the current working directory as process.cwd() is returning the directory of the node package. I initially assumed that since the code is being executed using a batch file as a wrapper (that is how bin files can execute without node at the beginning) then it is impossible but coffee-script manages to do it. I took a look at the coffee-script source but couldn't follow it (not experienced enough).

To test it for yourself create a package with this package.json file:

{
  "name": "test-package",
  "version": "1.0.0",
  "bin": {
    "test-package":  "./bin/test-package"
  },
  "main": "/lib/test"
}

this test-package file in bin:

#!/usr/bin/env node

var path = require('path');
var fs   = require('fs');
var lib  = path.join(path.dirname(fs.realpathSync(__filename)), '../lib');

require(lib + '/test');

Could anyone shed some light onto this.

and then try and get the command line directory inside lib/test.

解决方案

• process.cwd() returns directory where command has been executed (not directory of the node package) if it's has not been changed by 'process.chdir' inside of application.
• __filename returns absolute path to file where it is placed.
• __dirname returns absolute path to directory of __filename.

If you need to load files from your module directory you need to use relative paths.

require('../lib/test');

instead of

var lib  = path.join(path.dirname(fs.realpathSync(__filename)), '../lib');

require(lib + '/test');

It's always relative to file where it called from and don't depend on current work dir.

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