将响应正文保存到来自curl请求的文件 [英] Save Response Body to file from curl request
问题描述
我使用curl对webapi知道返回一个特定的post请求的文件（在浏览器中运行这将触发浏览器弹出一个保存文件对话框）。我的意图是将响应字节写入文件。我使用以下命令
Im using curl against a webapi which knows to return a file for a particular post request (running this within browser would trigger the browser to pop up a "save file" dialog) . My intention is to have the response bytes written to a file. I use the following command
curl -k -i -u username:password -X POST -H "Content-Type:application/json" -d @c:\\curl\\request_body_file.json -o config.cfg https://127.0.0.1:8000/myapi/trigger/export
这也会导致响应头被写入输出文件，这不是我的期望。我只需要保存响应内容。
This however causes also the response header to be written to the output file, which is not my desire. I only need the response content saved.
这是输出文件的外观：
TTP/1.1 200 OK
Content-Length: 12042
Content-Type: application/octet-stream; charset=UTF-8
Content-Disposition: attachment; filename=my_export
Date: Wed, 23 Oct 2013 09:30:47 GMT
Accept-Ranges: bytes
Server: Restlet-Framework/2.1.2
X-Auth-Token: Token ODVhMzk3OWY1NjcwMjg2ZGM0MDhmNTEzYTYwZmE4M2JhNTM1YmE0Yw==
xÚíÝÛãX~ØqÍÎŽçvfvervrevtrbyewd3334444 ................................
curl命令如何查看以前的描述。
How would the curl command look in order to achive what I previously described.
感谢
推荐答案
从curl文档：
-i，--include
-i, --include
（HTTP）在输出中包含HTTP标头。 HTTP头包括服务器名称，文档日期，HTTP版本等内容...
(HTTP) Include the HTTP-header in the output. The HTTP-header includes things like server-name, date of the document, HTTP-version and more...
因此删除-i参数
http://curl.haxx.se/docs/manpage.html
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