PHP命令行上的输出缓冲 [英] PHP Output buffering on the command line

问题描述

我有一个PHP脚本，我想在命令行上运行。此脚本需要加载包含PHP和HTML内容的PHP文件，并从该文件获取渲染的输出。

I have a PHP script that I want to run on the command line. This script, among other things, needs to load a PHP file that contains both PHP and HTML content and get the rendered output from that file.

这段代码完全符合我的需要，但不是从命令行运行时：

This code does exactly what I need, but not when run from the command line:

<?php

// ...
if(file_exists($content_file)) {
  ob_start();
  include($content_file);
  $content = ob_get_contents();
  ob_end_clean();
}

?>

在浏览器中运行时，我的脚本通过include（）获取PHP文件的输出，并将输出存储在$ content中。

When run in the browser, my script gets the rendered output of the PHP file via include(), and stores the output in $content.

但是，当我在命令行上执行这个脚本时，PHP文件的内容被回显，$ content永远不会设置。

However, when I execute this script on the command line, the contents of the PHP file are echoed out, and $content never gets set.

我搜索了文档，但似乎没有什么工作。调用ini_set（'implicit_flush'，false）没有效果，也没有ob_implicit_flush（0）;

I've searched the documentation, but nothing seems to work. Calling ini_set('implicit_flush', false) has no effect, nor does ob_implicit_flush(0);

任何想法？

推荐答案

我无法使用PHP 5.3重复此问题。

I am unable to duplicate this problem using PHP 5.3.

[charles@lobotomy ~]$ cat includeme.php
<?php

echo "Oh hi!\n";
?>
I am an include!

[charles@lobotomy ~]$ cat includehim.php
<?php

$content_file = './includeme.php';

if(file_exists($content_file)) {
  ob_start();
  include($content_file);
  $content = ob_get_contents();
  ob_end_clean();
}
[charles@lobotomy ~]$ php includehim.php
[charles@lobotomy ~]$

在交互式提示符下：

[charles@lobotomy ~]$ php -a
Interactive shell

php > $content_file = './includeme.php';
php > if(file_exists($content_file)) {
php {   ob_start();
php {   include($content_file);
php {   $content = ob_get_contents();
php {   ob_end_clean();
php { }
php >
php > echo $content;
Oh hi!
I am an include!

php > exit;

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