bash中两个数组的比较/差异 [英] Compare/Difference of two arrays in bash
问题描述
可以在bash中使用两个数组的差异。
如果你能建议我这样做,那真是太棒了。
代码:
Array1 =(key1key2key3key4key5key6 key7key8key9key10)
/ pre>
Array2 =(key1key2key3key4key5key6)
Array3 = diff (array1,array2)
Array3理想地应该是:
Array3 =(key7key8key9key10)
感谢您的帮助。
解决方案
Array1 - Array2
,
$ Array3 = for i in$ {Array1 [@]}; do
> skip =
> forin $ {Array2 [@]}; do
> [[$ i == $ j]] && {skip = 1;打破; }
> done
> [[-n $ skip]] || Array3 + =($ i)
> done
$ declare -p Array3
可以使用关联数组改进运行时,但我个人不会打扰。
对于像Dennis的对称差异answer,
comm
工作,只要我们按下输入和输出一点(因为他们工作在基于行的文件,而不是shell变量)。
shell使用换行符将数组连接成单个字符串,并且当从
comm
读取回到数组时舍弃制表符。
$ oldIFS = $ IFS IFS = $'\\\
\t'
$ Array3 =($(comm -3<(echo$ {Array1 [ *]})<(echo$ {Array2 [*]})))
comm:文件1不按排序顺序
$ IFS = $ oldIFS
$ declare - p Array3
declare -a Array3 ='([0] =key7[1] =key8[2] =key9[3] =key10)'
它抱怨,因为通过字典排序,
key1< ...< key9> key10
。但是由于两个输入数组的排序是相似的,忽略这个警告是很好的。您可以使用- nocheck-order
摆脱警告,或者添加|如果您不能保证输入数组的顺序和唯一性,请在
<(...)
过程替换中排序-uIs it possible to take the difference of two arrays in bash.
Would be really great if you could suggest me the way to do it.Code :
Array1=( "key1" "key2" "key3" "key4" "key5" "key6" "key7" "key8" "key9" "key10" ) Array2=( "key1" "key2" "key3" "key4" "key5" "key6" ) Array3 =diff(Array1, Array2) Array3 ideally should be : Array3=( "key7" "key8" "key9" "key10" )
Appreciate your help.
解决方案If you strictly want
Array1 - Array2
, then$ Array3=() $ for i in "${Array1[@]}"; do > skip= > for j in "${Array2[@]}"; do > [[ $i == $j ]] && { skip=1; break; } > done > [[ -n $skip ]] || Array3+=("$i") > done $ declare -p Array3Runtime might be improved with associative arrays, but I personally wouldn't bother. If you're manipulating enough data for that to matter, shell is the wrong tool.
For a symmetric difference like Dennis's answer, existing tools like
comm
work, as long as we massage the input and output a bit (since they work on line-based files, not shell variables).Here, we tell the shell to use newlines to join the array into a single string, and discard tabs when reading lines from
comm
back into an array.$ oldIFS=$IFS IFS=$'\n\t' $ Array3=($(comm -3 <(echo "${Array1[*]}") <(echo "${Array2[*]}"))) comm: file 1 is not in sorted order $ IFS=$oldIFS $ declare -p Array3 declare -a Array3='([0]="key7" [1]="key8" [2]="key9" [3]="key10")'It complains because, by lexographical sorting,
key1 < … < key9 > key10
. But since both input arrays are sorted similarly, it's fine to ignore that warning. You can use--nocheck-order
to get rid of the warning, or add a| sort -u
inside the<(…)
process substitution if you can't guarantee order&uniqueness of the input arrays.这篇关于bash中两个数组的比较/差异的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!