Php比较字符串和返回公共值 [英] Php compare strings and return common values

问题描述

我试图找到关于这个的其他帖子/信息，没有一个似乎工作，虽然我相信这是一个简单的任务。

I have tried to find other posts/information on this and none of them seem to work - although I'm sure this is a simple task.

两个字符串，我想有一些代码行，让我的单词，他们有共同的。

I have two strings, and I would like to have some lines of code that give me the word that they have in common.

例如，我可能有...

For example, I may have...

String1 = "Product Name - Blue";
String2 = "Blue Green Pink Black Orange";

我想有一个只包含值Blue的字符串。我如何做到这一点？提前感谢！

And I would like to have a string only containing the value Blue. How can I do this? Thanks in advance!

推荐答案

您可以使用explode 和 array_intersect 可能？

此处演示& 这里

<?php

  function common($str1,$str2,$case_sensitive = false)
  {
    $ary1 = explode(' ',$str1);
    $ary2 = explode(' ',$str2);

    if ($case_sensitive)
    {
      $ary1 = array_map('strtolower',$ary1);
      $ary2 = array_map('strtolower',$ary2);
    }

    return implode(' ',array_intersect($ary1,$ary2));
  }

  echo common('Product Name - Blue','Blue Green Pink Black Orange');

返回Blue;

strong> EDIT 将其更新为包含不区分大小写的版本。

EDIT Updated it to include a case-insensitive version if you'd like it.

这篇关于Php比较字符串和返回公共值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！