PHP字符串比较 [英] PHP String Comparison

问题描述

我有两个字符串，当我回音他们看起来一样，但当我 var_dump（）他们是不同的字符串类型：

I have two strings that look the same when I echo them, but when I var_dump() them they are different string types:

Echo:
http://blah
http://blah
var dump:
string(14) "http://blah"
string(11) "http://blah"
strToHex:
%68%74%74%70%3a%2f%2f%62%6c%61%68%00%00%00
%68%74%74%70%3a%2f%2f%62%6c%61%68

当我比较他们返回false。如何操作字符串类型，以便我可以执行返回true的比较。 string 11和string 14之间有什么区别？我相信有一个简单的决议，但还没有发现任何东西，无论我如何implode，爆炸，UTF8编码等字符串，他们不会比较或更改类型。

When I compare them they return false. How can I manipulate the string type so that I can perform a comparison that returns true. What is the difference between string 11 and string 14? I am sure there is a simple resolution but have not found anything yet, no matter how I implode, explode, UTF8 encode etc the strings they will not compare or change type.

感谢您的帮助！

彼得。

推荐答案

$ clean_str = trim（$ str ）;

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