javac：编译使用其中的类的.java文件 [英] javac : Compiling a .java file which uses other classes in it

问题描述

HI我有3个java文件

  a.java 
 b.java 
 c.java 
  

我设法使用

为a和b生成.class文件

  javac example / a.java 
 javac example / b.java 
  

但是当我对c.java也这样做时得到错误
错误：找不到符号b和c

<任何建议，如何我可以解决这个问题？

所有Java文件都在同一个文件夹中

解决方案

当你尝试编译类 c c时，必须有类 a 和 b / code>。这允许编译器验证它们存在，弄清楚他们有什么方法等。

javac 对程序包名称和类路径敏感。最简单的做法是同时编译所有三个，像这样 javac example / a.java example / b.java example / c.java 。

如果你转到example的父目录（我们称之为 src ），那么你可以运行以下命令：

  javac -cp src src / example / c.java 
  

你必须这样做的原因是因为你的类的包被列为 example 。由于您的程序包名称， javac 正在其类路径中寻找示例目录，其中希望找到 a.class 和 b.class 。

HI i have 3 java files

a.java  
b.java  
c.java  

I managed to generate .class files for both a and b using

javac example/a.java  
javac example/b.java  

but when i do the same for c.java I get the error error: cannot find symbol b and c

Any suggestions on how i could solve this problem ?

All the java files are in the same folder

解决方案

You have to have classes a and b in your classpath when you try to compile class c. This allows the compiler to verify that they exist, figure out what methods they have, etc.

javac is pretty sensitive to package names and classpaths. The easiest thing to do is to compile all three at the same time like so javac example/a.java example/b.java example/c.java.

If you go to the parent directory of example (let's call it src), then you can run the following:

javac -cp src src/example/c.java

The reason you have to do it this way is because your classes have their packages listed as example. Because of your package name, javac is looking for the example directory in its classpath, where it expects to find a.class and b.class.

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