javac如何自动编译类的依赖关系 [英] How does javac automatically compile dependencies of a class

问题描述

鉴于以下目录结构：

/top
   |--- wrk
          |--- pkg
                  |--- A.java
                  |--- B.java

假设两个文件 A.java 和 B.java 分别包含以下代码：

Assume that the two files A.java and B.java contain the following code, respectively:

// Filename: A.java
package pkg;
class A { B b; }

// Filename: B.java
package pkg;
class B {...}

假设当前目录是 / top / wrk

为什么命令 javac -cp。 pkg / A.java 成功工作，即使我们还没有编译 B.java ？

Why does the command javac -cp . pkg/A.java work successfully even though we have not yet compiled B.java?

此外，如果当前目录是 / top / wrk / pkg ，则命令 javac A.java 有效。怎么会这样？

Also if the current directory is /top/wrk/pkg then the command javac A.java works. How so?

推荐答案

为什么命令javac -cp。 pkg / A.java工作成功，即使我们还没有编译B.java

Why does the command javac -cp . pkg/A.java work successfully even though we have not yet compiled B.java

当你编译 A .java ，编译器将编译 B.java 以及 A.java 和 B.java 在同一个包中。即使 B.java 与 A.java 不同，也可以使用此功能（提供 wrk 目录中并且您编译 A.java 是公共的） / code>来自 wrk 目录。

When you compile A.java, the compiler will compile B.java as well since both A.java and B.java are in the same package. This will work even If B.java was in a different package from A.java (provided B is public) as long as both the packages are present in the wrk directory and you compile A.java from wrk directory.

来自 javac 的：

如果未指定-sourcepath选项，则还会在用户类路径中搜索源文件。

If the -sourcepath option is not specified, the user class path is also searched for source files.

来自 Oracle文档 CLASSPATH

类路径的默认值是。

The default value of the class path is "."

如果你还没有设置 CLASSPATH ，它将会默认为。。随后， sourcepath 也将是。，因为默认的 sourcepath 与 CLASSPATH 相同。您可以通过使用 javac编译 A.java 来确认默认源路径设置为。 -verbose -g pkg \A.java 。请注意，编译器在当前目录中查找 .java 文件：

If you haven't set a CLASSPATH, it will be defaulted to .. Subsequently, the sourcepath will also be . since the default sourcepath is the same as the CLASSPATH. You can confirm that the default sourcepath is set to . by compiling A.java using javac -verbose -g pkg\A.java. Notice that the compiler is looking in the current directory for .java files :

[解析开始pkg\A.java]
[解析完成29ms]
[源文件的搜索路径：[。]]

要确认 sourcepath 设置为 CLASSPATH ，您可以尝试更改 CLASSPATH 使用 -cp 选项，使用<$ c编译 A.java $ c> javac -cp C：\ -verbose -g pkg \A.java 。 A.java 这次不会编译，因为你已经将 CLASSPATH 覆盖到 C：\\ \\ ，这也是默认的 sourcepath 。这是输出：

To confirm that the sourcepath is set to CLASSPATH, you can try changing the CLASSPATH using the -cp option by compiling A.java using javac -cp C:\ -verbose -g pkg\A.java. A.java will not compile this time since you have overwritten the CLASSPATH to C:\ and that's what sourcepath will default to as well. This is the output :

[解析已启动pkg \A.java]
[解析完成26ms]
[源文件的搜索路径：[C：\]]
pkg \A.java:3：找不到符号
符号：B类

此外，如果当前目录是/ top / wrk / pkg，那么命令javac
A.java也可以。怎么样？

Also if the current directory is /top/wrk/pkg then the command javac A.java works. How so?

无论 B.class 是否为零，这都行不通出现在 pkg

This will not work regardless of whether B.class is present in pkg

免责声明：我只能在Windows上确认此行为，但我非常怀疑它在其他操作系统上应该有什么不同。

Disclaimer : I can only confirm this behavior on Windows but I highly doubt that it should be any different on other operating systems.

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