如何停止C ++控制台应用程序立即退出？ [英] How to stop C++ console application from exiting immediately?

问题描述

最近，我一直在尝试从此网站学习C ++。不幸的是，每当我尝试运行一个代码示例，我看到该程序打开约半秒，然后立即关闭。有没有办法阻止程序立即关闭，以便我可以看到我的努力的成果？

Lately, I've been trying to learn C++ from this website. Unfortunately whenever I try to run one of the code samples, I see that program open for about a half second and then immediately close. Is there a way to stop the program from closing immediately so that I can see the fruits of my effort?

推荐答案

编辑：正如Charles Bailey在下面的注释中正确地指出，如果有在 stdin 中缓冲的字符，这将不起作用，并且真的没有好的方法解决这个问题。如果您使用附加的调试器运行，请 John Dibling的建议解决方案可能是您问题的最干净的解决方案。

As Charles Bailey rightly points out in a comment below, this won't work if there are characters buffered in stdin, and there's really no good way to work around that. If you're running with a debugger attached, John Dibling's suggested solution is probably the cleanest solution to your problem.

也就是说，我会离开这里，也许别人会发现它有用。在开发过程中编写测试时，我已经用了很多方法。

That said, I'll leave this here and maybe someone else will find it useful. I've used it a lot as a quick hack of sorts when writing tests during development.

main 函数，您可以调用 std :: getchar（）;

At the end of your main function, you can call std::getchar();

$ c> stdin ，从而给你按任意键继续排序的行为（如果你真的想要一个按任意键消息，你必须自己打印一个）。

This will get a single character from stdin, thus giving you the "press any key to continue" sort of behavior (if you actually want a "press any key" message, you'll have to print one yourself).

您需要 #include< cstdio> 为 getchar 。

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