Yii不能实例化控制器 [英] Yii cannot Instantiate controller

问题描述

当我看到我们想实例化一个模型（例如名为 Post ）时，我们只需要调用：

As I see if we want to instantiate a Model (for example named Post), we just have to call:

$post = new Post();

现在，我还想实例化一个 Controller （例如命名为 Post ，并且此控制器的php文件名为 PostController.php ）。所以我使用这个代码：

Now, I also want to instantiate a Controller (for example named Post, and php file for this controller named PostController.php). So I use this code:

$postController = new PostController();

但是，运行此代码时会出现错误。

However, I get an error when running this code.

我做了一些搜索，发现它应该像下面的实例化：

I did some searching and found that it should be like the following to instantiate:

$postController = Yii::app()->createController('post/index');

它可以正常运行。但是我仍然想知道为什么第一种方法不起作用。

It runs correctly. But I still wonder why the first approach doesn't work?

推荐答案

回答你的确切问题为什么第一种方法不工作。
文件夹 / protected / controller 在项目的包含路径中为 NOT 。

Answering your exact question "why the first approach doesn't work". The folder /protected/controller is NOT in "include path" of the project.

只需将'import'=> array（'application.controllers。*'）添加到您的配置文件或使用
include（Yii :: app（） - > getBasePath（）。DIRECTORY_SEPARATOR.'controllers'.DIRECTORY_SEPARATOR.'PostController.php'）;

Just add 'import'=>array('application.controllers.*') into your config file or use include(Yii::app()->getBasePath().DIRECTORY_SEPARATOR.'controllers'.DIRECTORY_SEPARATOR.'PostController.php');

就是在创建PostController对象之前。 Ah和创建新的控制器需要这个控制器的名称，所以它应该是像

just before creating an object of PostController. Ah and creating new controller requires a name for this controller, so it should be something like

$ controller = new PostController（'post_controller'）;

我想指出，这种类型的控制器创建在Yii中是无用的，因为你创建一个完全独立于项目的控制器，因此它将几乎无用。正如你所说，创建控制器的正确方法是通过 Yii :: app（） - > createController（）

I would like to point out that this type of controller creation is useless in Yii, as you are creating a controller completely separated from project, so it will be almost useless. As you noted, the correct way to create controller is through Yii::app()->createController()

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