在Play scala中实现您自己的对象类型的Route参数的对象绑定器 [英] Implement your own object binder for Route parameter of some object type in Play scala

问题描述

嗯，我想把我的String param从下面的Play scala中替换成我自己的对象，说MyObject

Well, I want to replace my String param from the following Play scala Route into my own object, say "MyObject"

 From GET /api/:id  controllers.MyController.get(id: String)

 To GET /api/:id  controllers.MyController.get(id: MyOwnObject)

任何想法如何做到这一点将不胜感激。

Any idea on how to do this would be appreciated.

推荐答案

使用 PathBindable 从路径而不是查询绑定参数。从逗号分隔的路径绑定ids的示例实现（无错误处理）：

Use PathBindable to bind parameters from path rather than from query. Sample implementation for binding ids from path separated by comma (no error handling):

public class CommaSeparatedIds implements PathBindable<CommaSeparatedIds> {

    private List<Long> id;

    @Override
    public IdBinder bind(String key, String txt) {
        if ("id".equals(key)) {
            String[] split = txt.split(",");
            id = new ArrayList<>(split.length + 1);
            for (String s : split) {
                    long parseLong = Long.parseLong(s);
                    id.add(Long.valueOf(parseLong));
            }
            return this;
        }
        return null;
    }

    ...

}

$ b b

示例路径：

Sample path:

/data/entity/1,2,3,4

路线输入示例：

GET /data/entity/:id    controllers.EntityController.process(id: CommaSeparatedIds)

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