将ZipEntry复制到新的ZipFile中的惯用方法是什么？ [英] What is the idiomatic way to copy a ZipEntry into a new ZipFile?

问题描述

我在写一个工具，在DOCX文件中做一些小的文本替换，这是一个压缩格式。我的方法是使用 ZipOutputStream 将 ZipEntry 内容从原始文件中的条目复制到修改的文件。对于大多数DOCX文件，这很好，但偶尔我会遇到 ZipException 关于我写的内容和元信息之间的差异包含在 ZipEntry （通常是压缩大小的差异）。

I'm writing a tool to do some minor text replacement in a DOCX file, which is a zipped format. My method is to copy ZipEntry contents from entries in the original file into the modified file using a ZipOutputStream. For most DOCX files this works well, but occasionally I will encounter ZipExceptions regarding discrepancies between the contents I've written and the meta-information contained in the ZipEntry (usually a difference in compressed size).

这里是我用来复制内容的代码。为了简洁，我已经省略了错误处理和文档处理;我到目前为止还没有文档条目的问题。

Here's the code I'm using to copy over contents. I've stripped out error handling and document processing for brevity; I haven't had issues with the document entry so far.

ZipFile         original = new ZipFile(INPUT_FILENAME);
ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(OUTPUT_FILE));
Enumeration     entries = original.entries();
byte[]          buffer = new byte[512];
while (entries.hasMoreElements()) {
    ZipEntry    entry = (ZipEntry)entries.nextElement();
    if  ("word/document.xml".equalsIgnoreCase(entry.getName())) {
        //perform special processing
    }
    else{
        outputStream.putNextEntry(entry);
        InputStream in = original.getInputStream(entry);
        while (0 < in.available()){
            int read = in.read(buffer);
            outputStream.write(buffer,0,read);
        }
        in.close();
    }
    outputStream.closeEntry();
}
outputStream.close();

直接复制 ZipEntry 对象从一个 ZipFile 到另一个？

What is the proper or idiomatic way to directly copy ZipEntry objects from one ZipFile to another?

推荐答案

发现了一个避免错误的解决方法。通过创建一个新的 ZipEntry 只有名称字段设置，我可以复制内容没有问题。

I have found a workaround that avoids the error. By creating a new ZipEntry with only the name field set I'm able to copy over contents without issue.

ZipFile         original = new ZipFile(INPUT_FILENAME);
ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(OUTPUT_FILE));
Enumeration     entries = original.entries();
byte[]          buffer = new byte[512];
while (entries.hasMoreElements()) {
    ZipEntry    entry = (ZipEntry)entries.nextElement();
    if  ("word/document.xml".equalsIgnoreCase(entry.getName())) {
        //perform special processing
    }
    else{
        // create a new empty ZipEntry
        ZipEntry newEntry = new ZipEntry(entry.getName()); 
//      outputStream.putNextEntry(entry);
        outputStream.putNextEntry(newEntry);
        InputStream in = original.getInputStream(entry);
        while (0 < in.available()){
            int read = in.read(buffer);
            outputStream.write(buffer,0,read);
        }
        in.close();
    }
    outputStream.closeEntry();
}
outputStream.close();

< > ZipEntry （eg：comment，extra）。 API文档并不清楚这是否重要。

However, I this method loses any meta-information stored in the fields of original ZipEntry (e.g.: comment, extra). The API docs aren't clear on whether this is important.

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