LESS - 通过循环两个变量创建ID [英] LESS - Create ID by looping through two variables

问题描述

我试图创建一个循环，输出坐标-2，-2到2,2之间的所有可能的组合。有没有办法做到这一点，而不创建多个循环？

I am trying to create a loop that outputs all of the possible combinations between coordinates -2,-2 to 2,2. Is there any way to do this without creating multiple loops?

#p1x0,#p2x0,#p-1x0,#p-2x0,#p1x1,#p-1x-1,#p-1x1,#p1x-1,#p2x2,#p-2x-2,p2x-2,p-2x2,#p2x1,#p2x-1,#p1x2,#p1x-2,#p-2x1,#p-2x-1,#p-1x2,#p-1x-2,#p0x-1,#p0x-2,#p0x0,#p0x1,#p0x2{}

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当前尝试

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Current Attempt

#cube-side {
border:red;
}

.create-cubes(@n, @i: -2, @z: -2, @side-sum:@i + @z) when (@side-sum =< @n) {
    & when (@i < @z) {
        .create-cubes(@n, @i+1);
    }
    & when (@z < @i) {
        .create-cubes(@n, @z+1);
    }
    #p@{i}x@{z}:extend(#cube-side) {}
}

.create-cubes(4);

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输出

b $ b

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Output

#cube-side,
#p-2x-2 {
  border: red;
}

推荐答案

/ o any loops at all：

There's way to do this w/o any loops at all:

#cube-side {
    border: red;
}

-2, -1, 0, 1, 2 {
    #p&x&:extend(#cube-side) {}
}

虽然对于一个任意的值列表，一个嵌套循环是最简单的解决方案（参见 example ），例如（pure Less）：

Though for an arbitrary list of values just a nested loop is the simplest solution of course (see for example), e.g. (in "pure Less") something like:

.create-cubes(-2, 2);
.create-cubes(@min, @max) {
    .i; .i(@i: @min) when (@i <= @max) {
        .j; .i(@i + 1);
    }
    .j(@j: @min) when (@j <= @max) {
        #p@{i}x@{j}:extend(#cube-side) {}
        .j(@j + 1);
    }
}

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