创建两个日期的循环 [英] Creating a loop for two dates
问题描述
可能重复:
通过Python中的一系列日期迭代
我有两个条目:
date1 = 2004.09.25
date2 = 2004.10.08
我想在Python中编写一个可识别日期范围并打印的脚本。如下所示:
I want to wrote a script in Python that recognizes the date range and print them. something like this:
for i in range(date1:date2):
print i
我需要以日期的特定格式定义日期吗?
预期输出如下:
Do I need to define the dates in a particular format for dates? The expected output is like:
2004.09.25
2004.09.26
.
.
.
2004.10.08
推荐答案
你的第一步应该一直在看python datetime库。
Your first step should have been to look at the python datetime library.
总的来说,你的第一个解决方案可能是这样的:
Overall, your first solution could look something like this:
date1 = datetime.date(2004, 9, 25)
date2 = datetime.date(2004, 10, 8)
day = datetime.timedelta(days=1)
while date1 <= date2:
print date1.strftime('%Y.%m.%d')
date1 = date1 + day
(需要注意的是:这显然会使您的 date1
变量)
(one thing to note: this will obviously clobber your date1
variable)
我稍后会将其重构为daterange函数,以便您可以做更接近您所做的事情;在daterange(date1,date2)中,d将显示为
I would later refactor this into a daterange function so that you can do something closer to what you did; it would look like
for d in daterange(date1, date2):
print d.strftime('%Y.%m.%d')
之后,当你开发你的python技能,它可以喜欢像这样:
Later on, when you develop your python skills, it could like like this:
for i in range((date2 - date1).days + 1):
print (date1 + datetime.timedelta(days=i)).strftime('%Y.%m.%d')
或者这是我的最终版本:
Or this, which would be my final version:
def daterange(d1, d2):
return (d1 + datetime.timedelta(days=i) for i in range((d2 - d1).days + 1))
for d in daterange(date1, date2):
print d.strftime('%Y.%m.%d')
这篇关于创建两个日期的循环的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!