活动子项父项的复杂CSS选择器 [英] Complex CSS selector for parent of active child

问题描述

有没有办法根据类中的子元素的类来选择父元素？与我相关的示例，该示例与 http://drupal.org 的精美菜单插件的HTML输出相关。输出呈现如下：

 < ul class =menu> 
< li> 
< a class =active>活动页< / a> 
< / li> 
< li> 
< a>一些其他页面< / a> 
< / li> 
< / ul> 
  

我的问题是，是否可以对包含锚点的列表项应用样式用活动类就可以了。显然，我更喜欢列表项标记为活动，但我不能控制生成的代码。我可以使用javascript来执行这种事情（JQuery不介意），但我想知道是否有一个方法使用CSS选择器。

只是为了

解决方案

不幸的是，没有办法做到这一点

$ b // JavaScript代码：
document.getElementsByClassName（active）[0] .parentNode;

// jQuery代码：
$（'。active'）。parent（）。get（0）; //这将是< a>的父级< li> ;.

Is there a way to select a parent element based on the class of a child element in the class? The example that is relevant to me relating to HTML output by a nice menu plugin for http://drupal.org. The output renders like this:

<ul class="menu">  
    <li>  
        <a class="active">Active Page</a>  
    </li>  
    <li>    
        <a>Some Other Page</a>  
    </li>  
</ul>  

My question is whether or not it is possible to apply a style to the list item that contains the anchor with the active class on it. Obviously, I'd prefer that the list item be marked as active, but I don't have control of the code that gets produced. I could perform this sort of thing using javascript (JQuery springs to mind), but I was wondering if there is a way to do this using CSS selectors.

Just to be clear, I want to apply a style to the list item, not the anchor.

解决方案

Unfortunately, there's no way to do that with CSS.

It's not very difficult with JavaScript though:

// JavaScript code:
document.getElementsByClassName("active")[0].parentNode;

// jQuery code:
$('.active').parent().get(0); // This would be the <a>'s parent <li>.

这篇关于活动子项父项的复杂CSS选择器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！