如何以小时显示timedelta：min：sec？ [英] How can I display timedelta in hours:min:sec?

问题描述

我正在导出一个timedeltas的列表到csv和天真的混乱了格式。我试过这个：

I am exporting a list of timedeltas to csv and the days really messes up the format. I tried this:

 while time_list[count] > datetime.timedelta(days = 1):
        time_list[count] = (time_list[count] - datetime.timedelta(days =  1)) + datetime.timedelta(hours = 24)

但它立即转换回天，并创建一个无限循环。

But it's instantly converted back into days and creates an infinite loop.

推荐答案

默认情况下， str（） $ c> timedelta 将始终包括天部分。在内部，该值总是标准化为天数，秒和微秒，因此没有时间将转换天数转换为小时，因为没有跟踪单独的小时组件。

By default the str() conversion of a timedelta will always include the days portion. Internally, the value is always normalised as a number of days, seconds and microseconds, there is no point in trying to 'convert' days to hours because no separate hour component is tracked.

如果您要以不同的方式格式化 timedelta（）对象，您可以轻松地手动进行：

If you want to format a timedelta() object differently, you can easily do so manually:

def format_timedelta(td):
    minutes, seconds = divmod(td.seconds + td.days * 86400, 60)
    hours, minutes = divmod(minutes, 60)
    return '{:d}:{:02d}:{:02d}'.format(hours, minutes, seconds)

这将忽略任何微秒部分，但这是微不足道的：

This ignores any microseconds portion, but that is trivially added:

return '{:d}:{:02d}:{:02d}.{:06d}'.format(hours, minutes, seconds, td.microseconds)

演示：

>>> format_timedelta(timedelta(days=2, hours=10, minutes=20, seconds=3))
'58:20:03'
>>> format_timedelta(timedelta(hours=10, minutes=20, seconds=3))
'10:20:03'

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