更新了vba代码，仍然它给我一个下标超出范围的错误 [英] Updated the vba code and still it gives me a subscript out of range error

问题描述

此代码仍然会给我一个下标错误

This code still gives me an out of subscript error

Sub importData2()

  ChDir "C:\Users\Desktop\Java"
  Dim filenum(0 To 10) As Long
  filenum(0) = 052
  filenum(1) = 060
  filenum(2) = 064
  filenum(3) = 068
  filenum(4) = 070
  filenum(5) = 072
  filenum(6) = 074
  filenum(7) = 076
  filenum(8) = 178
  filenum(9) = 180
  filenum(10) = 182

  Dim sh1 As Worksheet
  Dim rng As Range
  Set rng = Range(Selection, ActiveCell.SpecialCells(xlLastCell))
  Dim wb As Workbook
  Set wb = Application.Workbooks("30_graphs_w_Macro.xlsm")

  Dim sh2 As Worksheet
  Dim rng2 As Range
  Set rng2 = Range("A69")
  Dim wb2 As Workbook

  For lngposition = LBound(filenum) To UBound(filenum)
    Set wb2 = Application.Workbooks.Open(filenum(lngposition) & ".csv")
    wb2.Worksheets(filenum(lngposition)).rng.Copy wb.Worksheets(filenum(lngposition)).rng2.Paste
  Next lngposition

my_handler:
  MsgBox "All done."
End Sub

这还是给我一个下标错误的行： p>

This still gives me an out of subscript error on the line:

Set wb2 = Application.Workbooks(filenum(lngposition) & ".csv")

我避免使用.active和.select。 .select。

I avoided using .active and .select. .select.

推荐答案

下标超出范围如果所需的文件尚未打开。

Subscript out of Range would raise on that line if the required file is not already open.

由于似乎不太可能已经有11个文件打开，您可能需要使用 Open

Since it seems unlikely that you would already have 11 files open, you probably need to use the Open method to open the necessary workbook inside your loop.

设置wb2 = Application.Workbooks.Open（filenum（lngposition ）&.csv）。

更新您的代码 b $ b

Sub importData2()

  ChDir "C:\Users\Desktop\Java"
  Dim filenum(0 To 10) As String
  Dim wb As Workbook
  Dim sh1 As Worksheet
  Dim rng As Range
  Dim wb2 As Workbook
  Dim sh2 As Worksheet
  Dim rng2 As Range 

  filenum(0) = "052"
  filenum(1) = "060"
  filenum(2) = "064"
  filenum(3) = "068"
  filenum(4) = "070"
  filenum(5) = "072"
  filenum(6) = "074"
  filenum(7) = "076"
  filenum(8) = "178"
  filenum(9) = "180"
  filenum(10) = "182"


  '## What workbook is this referring to?? This might cause problems later...
  Set rng = Range(Selection, ActiveCell.SpecialCells(xlLastCell))
  Set rng2 = Range("A69")
  Set wb = Application.Workbooks("30_graphs_w_Macro.xlsm")

  For lngposition = LBound(filenum) To UBound(filenum)

    Set wb2 = Application.Workbooks.Open(filenum(lngposition) & ".csv")

    Set sh1 = wb.Worksheets(filenum(lngposition))

    Set sh2 = wb2.Worksheets(1)  'A CSV file only has 1 worksheet.

    sh2.rng.Copy Destination:=sh1.Range(rng2.Address)
  Next lngposition

my_handler:
  MsgBox "All done."
End Sub

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