从CSV中删除线 [英] Removing lines from a CSV

问题描述

我有一个csv文档，其中包含多个标题：

I have a csv document with multiple headers like:

"Date","RQ","PM","SME","Activity","Status code"
"2/2/12","6886","D_WV","John Smith","Recent","2004"

和一个只是状态代码列表的文本文档，每行一个。

and a text document that is just a list of status codes, one per line.

我试图找出如何从包含来自文本文件的状态代码的CSV。

I am trying to figure out how to remove all lines from the CSV that contain the status codes from the text file.

到目前为止，我已经尝试使用：

So far I have tried using:

$m = gc textfile.txt
Select-String data.csv -Pattern $m -NotMatch

$ b然而，这留给我额外的数据，如

However that leaves me with extra data such as

data.csv:1"Date","RQ","PM","SME","Activity","Status code"
data.csv:2"2/2/12","6886","D_WV","John Smith","Recent","2004"

我也尝试过：

gc data.csv | ? { $_ -notlike $m }

使用正确的格式，但不想删除任何价值。任何帮助是非常感谢。

That uses the proper formatting but does not want to remove any of the values. Any help is much appreciated.

推荐答案

来自select-string的matchinfo对象可能会让人困惑。
这需要什么？

Those matchinfo objects from select-string can be confusing. Does this do what you need?

$m = gc textfile.txt
select-string data.csv -pattern $m -notmatch |
select -expand line

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