在Ruby中将csv转换为json [英] Convert csv to json in ruby

问题描述

CSV

id,modifier1_name,modifier2_price,modifier2_name,modifier2_price,modifier2_status
1,'Small',10,'Large',20,'YYY'
2,'Small',20,'Large',30,'YYY'

JSON

[
{
 id: 1,
 modifier: [
   {name: 'Small', price: 10},
   {name: 'Large', price: 20, status: 'YYY'}]
},
{
 id: 2,
 modifier: [
   {name: 'Small', price: 20},
   {name: 'Large', price: 30, status: 'YYY'}],
}
]

在这种情况下，当修饰符可以不同时，将CSV转换为Json？

How to convert CSV to Json in this case when modifiers can be different ?

推荐答案

您需要自己映射修饰符，没有内置的方法从您的逻辑将散列值映射到数组：

You will need to map the modifiers yourself, as there is no built-in method to map hash values into an array from your logic:

JSON.pretty_generate(CSV.open('filename.csv', headers: true).map do |row|
  modifier = {}
  row.each do |k, v|
    if k =~ /modifier(.)_(.*)$/
      (modifier[$1] ||= {})[$2] = v
    end
  end
  { id: row['id'],
    modifier: modifier.sort_by { |k, v| k }.map {|k, v| v }
  }
end)

对于文件*

id,modifier1_name,modifier1_price,modifier2_name,modifier2_price,modifier2_status
1,Small,10,Large,20,YYY
2,Small,20,Large,30,YYY

_{文件，因为它不会给你所需的结果 - 你两次修改modifier2_price，例如}

你会得到：

[
  {
    "id": "1",
    "modifier": [
      {
        "name": "Small",
        "price": "10"
      },
      {

        "name": "Large",
        "price": "20",
        "status": "YYY"
      }
    ]
  },
  {
    "id": "2",
    "modifier": [
      {
        "name": "Small",
        "price": "20"
      },
      {
        "name": "Large",
        "price": "30",
        "status": "YYY"
      }
    ]
  }
]

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