Matlab fprintf正确格式说明符,用于四舍五入到14个小数位 [英] Matlab fprintf correct format specifier for rounding to 14 decimal places
问题描述
我使用下面提供的代码来读取矩阵,并在每个值的末尾应用分号(;
)和换行符。
I am using the code presented below to read a matrix and apply a semicolon (;
) and newline at the end of every value.
我有精度格式说明符的问题。代码块下面是csv输出中的一行。您可以看到第5列和第6列格式正确,但有指数值,我需要四舍五入到14个小数位。为什么第4行的'%f.14'不是这样做的?
I am having problems with the precision format specifier. Below the code block is a line from the csv output. You can see that columns 5 and 6 are formatted properly, but there are exponential values that I need rounded to 14 decimal places. Why isn't the '%f.14'on line 4 doing this? I thought it didn't use exponential notation?
function write_to_csv(filepath, decision)
csv = fopen('matrix.csv', 'a+');
for ii = 1:length(decision)
format = '%d; %f.14';
fprintf(csv, format, decision(ii));
end
fprintf(csv,'\n')
fclose(csv);
end
1; 1.032204e-03; -2.580511e-04; 1; 32190201170708; 17682101210450; 2; 7.600000e-01; -1;
1; 1.032204e-03; -2.580511e-04; 1; 32190201170708; 17682101210450; 2; 7.600000e-01; -1;
Credit to MChandler for supplying the above code from question: Add a delimiter to end of each line of csv file MATLAB
推荐答案
这取决于变量 decision
的格式。由于在%f.14
之前有%d
,它将渲染一维矩阵为%d
。它将完全忽略定点格式说明符。如果你的矩阵决定确实是一维的,使用 format ='%.14f';
如注释中所述:
This depends on the format of the variable decision
. Since you have %d
before the %f.14
it will render a 1-dimensional matrix as only %d
. It will completely ignore the fixed point format specifier. If your matrix decision is indeed 1-dimensional, use format = '%.14f';
as mentioned in the comments:
function write_to_csv(filepath, decision)
csv = fopen('matrix.csv', 'a+');
for ii = 1:length(decision)
format = '%.14f';
fprintf(csv, format, decision(ii));
end
fprintf(csv,'\n')
fclose(csv);
end
您可以在这里阅读格式说明符: https://www.mathworks.com/help/matlab/matlab_prog/formatting-strings .html#bq0z60p-1
You can read up on format specifiers here: https://www.mathworks.com/help/matlab/matlab_prog/formatting-strings.html#bq0z60p-1
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