如何在shell脚本中的curl命令中传递变量 [英] How to pass a variable in a curl command in shell scripting

问题描述

我有一个curl命令：

I have a curl command:

curl -u ${USER_ID}:${PASSWORD} -X GET 'http://lppma670.gso.aexp.com:8080/rest/job-execution/job-details/${job_id}'

变量 job_id 在其中有一个值，例如1160.当我在shell中执行curl命令时，它给我以下错误： p>

The variable job_id has a value in it, say, 1160. When I execute the curl command in shell it gives me the following error:

{"message":"Sorry. An unexpected error occured.", "stacktrace":"Bad Request. The request could not be understood by the server due to malformed syntax."}

如果我直接通过数字1160该命令如下所示，curl命令工作。

If I pass the number '1160' directly in the command, as shown below, the curl command works.

curl -u ${USER_ID}:${PASSWORD} -X GET 'http://lppma670.gso.aexp.com:8080/rest/job-execution/job-details/1160'

有人可以帮我吗？

推荐答案

在 shell ，你只能使用双引号，而不是单引号：单引号不展开。
了解'和和`之间的区别。请参见 http://mywiki.wooledge.org/Quotes 和 http://wiki.bash-hackers.org/syntax/words

When using variables in shell, you can only use doubles quotes, not single quotes : the variables inside single quotes are not expanded. Learn the difference between ' and " and `. See http://mywiki.wooledge.org/Quotes and http://wiki.bash-hackers.org/syntax/words

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