将curl示例转换为pycurl [英] Convert curl example to pycurl
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问题描述
有人可以将以下PostMark curl示例转换为pycurl？
Could someone convert the following PostMark curl example to pycurl?
curl -X POST "http://api.postmarkapp.com/email" \
-H "Accept: application/json" \
-H "Content-Type: application/json" \
-H "X-Postmark-Server-Token: ed742D75-5a45-49b6-a0a1-5b9ec3dc9e5d" \
-v \
-d "{From: 'sender@example.com', To: 'receiver@example.com', Subject: 'Postmark test', HtmlBody: '<html><body><strong>Hello</strong> dear Postmark user.</body></html>'}"
推荐答案
你可以使用这样的东西。这是一个基本的实现，但它应该工作。
You can use something like this. It's a basic implementation but it should work.
import pycurl, json
github_url = 'https://api.postmarkapp.com/email'
data = json.dumps({"From": "user@example.com", "To": "receiver@example.com", "Subject": "Pycurl", "TextBody": "Some text"})
c = pycurl.Curl()
c.setopt(pycurl.URL, github_url)
c.setopt(pycurl.HTTPHEADER, ['X-Postmark-Server-Token: API_TOKEN_HERE','Accept: application/json'])
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS, data)
c.perform()
这篇关于将curl示例转换为pycurl的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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