将带括号的网址传递到curl [英] Passing a URL with brackets to curl

问题描述

如果我尝试将网址传递到包含括号的curl，则会失败并显示错误：

  $ curl'http ：//www.google.com/？TEST [] = 1'
 curl：（3）[globbing] pos 29范围规范中的非法字符
  
  $ curl'http://www.google.com/?TEST\ [\]=1'
  
有趣的是，我使用一个反斜杠来逃避 第一个括号，它失败时失败，错误代码为20497：
  $ curl'http://www.google.com/?TEST\[]=1'
 $ echo $！ 
 20497 
  
我的问题是如何解决这个一般情况？是否有自动转义URL的参数，或者在传递curl之前需要转义的字符的描述？
解决方案
 Nevermind，我发现它在文档：
  -g /  -  globoff 
此选项关闭 URL globbing解析器。当您设置此选项时，您可以
指定包含字母{} []的URL，而不必由curl 
本身解释。注意，这些字母不是正常的合法URL内容，而是应根据URI标准编码的
。 
  
 
If I try to pass a URL to curl that contains brackets, it fails with an error:
$ curl 'http://www.google.com/?TEST[]=1'
curl: (3) [globbing] illegal character in range specification at pos 29
However, if I escape both brackets, it appears to work:
$ curl 'http://www.google.com/?TEST\[\]=1'
Interestingly, I use a backslash to escape only the first bracket it fails silently with error code 20497:
$ curl 'http://www.google.com/?TEST\[]=1'
$ echo $!
20497
My question is how to fix this for general cases? Is there an argument that will escape URLs automatically, or a description of the characters that need to be escaped before passing to curl?
解决方案
Nevermind, I found it in the docs:
-g/--globoff
              This  option  switches  off  the "URL globbing parser". When you set this option, you can
              specify URLs that contain the letters {}[] without having them being interpreted by  curl
              itself.  Note  that  these  letters  are not normal legal URL contents but they should be
              encoded according to the URI standard.


                        
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