200 HTTP CODE在非url字符串 [英] 200 HTTP CODE at non-url strings

问题描述

$agent = "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)";
$ch=curl_init();
   curl_setopt ($ch, CURLOPT_URL,$url );
   curl_setopt($ch, CURLOPT_USERAGENT, $agent);
   curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);
   curl_setopt ($ch,CURLOPT_VERBOSE,false);
   curl_setopt($ch, CURLOPT_TIMEOUT, 5);
   curl_setopt($ch,CURLOPT_SSL_VERIFYPEER, FALSE);
   curl_setopt($ch,CURLOPT_SSLVERSION,3);
   curl_setopt($ch,CURLOPT_SSL_VERIFYHOST, FALSE);
   $page=curl_exec($ch);
   //echo curl_error($ch);
   $httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
   curl_close($ch);

我在我的项目中使用cUrl。我得到的HTTP网站的CODE。但是当我尝试asdasd（$ url =asdasd），返回的HTTP CODE是200。但是asdasd不是一个网站。为什么HTTP CODE是200？

I'm using cUrl at my project. I'm getting HTTP CODE of web sites. But when i try "asdasd" ($url="asdasd") , returned HTTP CODE is 200 . But "asdasd" isn't a web site. Why HTTP CODE is 200 ?

推荐答案

您可能首先要检查 curl_exec 的返回值。它在手册中说：

You might want to check the return value from curl_exec first. It says in the manual:

成功或 FALSE 返回 TRUE code> 。但是，如果设置了 CURLOPT_RETURNTRANSFER 选项，则会返回成功结果 FALSE 。

Returns TRUE on success or FALSE on failure. However, if the CURLOPT_RETURNTRANSFER option is set, it will return the result on success, FALSE on failure.

对于 curl_getinfo ，有一个旁注：

如果重新使用句柄，则保留此函数收集的信息。这意味着，除非统计信息被此函数内部覆盖，否则将返回上一个信息。

Information gathered by this function is kept if the handle is re-used. This means that unless a statistic is overridden internally by this function, the previous info is returned.

因此HTTP 200可能是以前的cURL调用的结果。

So that HTTP 200 might well be the result of a previous cURL invocation.

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