为什么Cygwin的GCC显示每个文件的第一行？ [英] Why does Cygwin's GCC display the first line of every file?

问题描述

我不是一个常规的Cygwin用户。我安装了Cygwin和Cygwin64来测试提议的补丁。

I'm not a regular Cygwin user. I installed Cygwin and Cygwin64 for testing proposed patches.

下面是一个典型的make的输出：

Here's the output of a typical make:

User@windows-7-x64 ~/cryptopp
$ make
g++ -DNDEBUG -g -O2 -fPIC -march=native -pipe -c shacal2.cpp
shacal2.cpp:1:0: warning: -fPIC ignored for target (all code is position independent)
 // shacal2.cpp - by Kevin Springle, 2003
 ^
g++ -DNDEBUG -g -O2 -fPIC -march=native -pipe -c seed.cpp
seed.cpp:1:0: warning: -fPIC ignored for target (all code is position independent)
 // seed.cpp - written and placed in the public domain by Wei Dai
 ^
g++ -DNDEBUG -g -O2 -fPIC -march=native -pipe -c shark.cpp
shark.cpp:1:0: warning: -fPIC ignored for target (all code is position independent)
 // shark.cpp - written and placed in the public domain by Wei Dai
 ^
...

Cygwin的make显示其编译的每个文件的第一行。

Cygwin's make displays the first line of every file it compiles.

为什么Cygwin的make显示每个文件的第一行？

Why does Cygwin's make display the first line of every file? How can I stop the behavior?

推荐答案

输出是由于关于 -fPIC 命令行选项，就像它说的。从您的makefile的 CXXFLAGS （或任何地方）移除 -fPIC 选项，它会消失。

The output is due to the warning about the -fPIC command line option, just as it says. Remove the -fPIC option from your makefile's CXXFLAGS (or wherever) and it will go away.

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