如何使用javascript合并对象 [英] How to merge objects using javascript
本文介绍了如何使用javascript合并对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我试图创建一个类似于下面的json对象:
I am trying to create a json object similar to the below:
[
{
"name":"aaa_aaaurf",
"region":"F&R",
"checkins":[[1,0],[2,0],[3,0],[4,3],[5,0],[6,0],[7,0],[8,3],[9,0],[10,0],[11,0],[12,0]],
"teamsize":[[1,0],[2,0],[3,0],[4,3],[5,0],[6,0],[7,0],[8,1],[9,0],[10,0],[11,0],[12,0]],
"Checkintimes":[[1,0],[2,0],[3,0],[4,184],[5,0],[6,0],[7,0],[8,0],[9,0],[10,0],[11,0],[12,0]]
},
{
"name":"aaa_accessservices",
"region":"F&R",
"checkins":[[1,0],[2,0],[3,0],[4,0],[5,0],[6,0],[7,0],[8,0],[9,0],[10,0],[11,27],[12,12]],
"teamsize":[[1,0],[2,0],[3,0],[4,0],[5,0],[6,0],[7,0],[8,0],[9,0],[10,0],[11,11],[12,11]],
"Checkintimes":[[1,0],[2,0],[3,0],[4,0],[5,0],[6,0],[7,0],[8,0],[9,0],[10,0],[11,10],[12,12]]
}]
我使用d3写了脚本,如何合并对象数组以获取json?
I have written the script using d3 but the object is getting overwritten with the latest one.How to merge the object array to get the json?
以下是代码:
var dataset;
var teamsize={};
var repository;
var sbu;
var index=0;
var teamsizearray = [];
var checkinsarray = [];
var checkintimesarray = [];
var ConsData = {};
var MergeData = {};
var tempData={};
d3.csv("bubblechart.csv", function(data, error) {
dataset = data;
alert(dataset.length);
//alert(error);
for(var x=0;x<dataset.length;x++)
{
if (x==0)
{
repository = dataset[0].repository;
}
if (dataset[x].repository!= repository)
{
if ((x > 0 ) || (x==dataset.length))
{
index = 1;
ConsData["name"] = repository;
ConsData["region"] = sbu;
ConsData["checkins"] = checkinsarray;
ConsData["teamsize"] = teamsizearray;
ConsData["Checkintimes"] = checkintimesarray;
tempData=ConsData;
jQuery.extend(MergeData, tempData);
teamsizearray = [];
checkinsarray = [];
checkintimesarray = [];
repository = dataset[x].repository;
sbu = dataset[x].BusinessUnit
checkinsarray.push([index, dataset[x].AvgCheckinCount]);
teamsizearray.push([index, dataset[x].TeamSize]);
checkintimesarray.push([index, dataset[x].MeanBuildTimeHrs]);
}
}
else
{
if (x ==0)
{
index=1;
}
else
{
index=index+1;
}
repository = dataset[x].repository;
sbu = dataset[x].BusinessUnit
checkinsarray.push([index, dataset[x].AvgCheckinCount]);
teamsizearray.push([index, dataset[x].TeamSize]);
checkintimesarray.push([index, dataset[x].MeanBuildTimeHrs]);
}
}
console.log(JSON.stringify(MergeData));
});
以下是csv数据。
aaa_aaaurf,1,2013,0,0,0,Financial&Risk
aaa_aaaurf,2,2013,0,0,0,Financial&Risk
aaa_aaaurf,3,2013,0,0,0,Financial&Risk
cCG_tzz,1,2013,5,3,100,Financial&Risk
cCG_tzz,2,2013,8,5,80,Financial&Risk
aCG_txz,1,2013,12,3,70,Financial&Risk
GCG_txz,1,2013,21,3,50,Financial&Risk
GCG_txz,2,2013,12,3,70,Financial&Risk
推荐答案
href =http://lodash.com/docs#merge =nofollow> lodash ?
Can you use lodash?
var names = {
'characters': [
{ 'name': 'barney' },
{ 'name': 'fred' }
]
};
var ages = {
'characters': [
{ 'age': 36 },
{ 'age': 40 }
]
};
_.merge(names, ages);
// → { 'characters': [{ 'name': 'barney', 'age': 36 }, { 'name': 'fred', 'age': 40 }] }
var food = {
'fruits': ['apple'],
'vegetables': ['beet']
};
var otherFood = {
'fruits': ['banana'],
'vegetables': ['carrot']
};
_.merge(food, otherFood, function(a, b) {
return _.isArray(a) ? a.concat(b) : undefined;
});
// → { 'fruits': ['apple', 'banana'], 'vegetables': ['beet', 'carrot] }
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