通过JavaScript变量PHP和AJAX，结果没有显示任何东西 [英] Pass javascript variable to php with ajax and the result doesn't show anything
问题描述
这是我的code，我想通过JavaScript变量与AJAX到PHP当我点击提交按钮，那么结果不从JavaScript什么code是错误的显示var_data变量？ 这是编辑才能的人之前大家帮我
This is my code and i want to pass javascript variable with ajax to php when i click submit button then the result doesn't show var_data variable from javascript What code is wrong? This is edit order one before everybody help me
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script>
$(document).ready(function() {
$('#sub').click(function() {
var var_data = "Hello World";
$.ajax({
url: 'http://localhost/ajax/PassVariable.php',
type: 'GET',
data: { var_PHP_data: var_data },
success: function(data) {
// do something;
}
});
});
});
</script>
</head>
<body>
<input type="submit" value="Submit" id="sub"/>
<?php
$test = $_GET['var_PHP_data'];
echo $test;
?>
</body>
</html>
这是源$ C $ C现在
and this is source code now
<?php
if (isset($_GET['var_PHP_data'])) {
echo $_GET['var_PHP_data'];
} else {
?>
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script>
$(document).ready(function() {
$('#sub').click(function() {
var var_data = "Hello World";
$.ajax({
url: 'http://localhost/test.php',
type: 'GET',
data: { var_PHP_data: var_data },
success: function(data) {
// do something;
$('#result').html(data)
}
});
});
});
</script>
</head>
<body>
<input type="submit" value="Submit" id="sub"/>
<div id="result">
</body>
</html>
<?php } ?>
这条语句，如果（使用isset（$ _ GET ['var_PHP_data']））输出错误再展世界您好我应该怎么做才能做使用isset（$ _ GET ['var_PHP_data']）是真的吗？
this statement if(isset($_GET['var_PHP_data'])) output false and then show Hello World What should i do to do for isset($_GET['var_PHP_data']) is true?
推荐答案
您解决方案具有PHP的问题：你不检查数据是否存在，而且，你不这样做，结果什么。我已经修改了脚本执行以下操作：
Your solution has PHP issues: you don't check if the data exists, and also, you don't do anything with the result. I've modified the script to do the following:
- 检查var_PHP_data变量被设置（在PHP中，在服务器上）。
- 如果是的，只是发送一个空白的文本响应包含的数据。
- 如果没有，再画的形式和其他一切。
- 在窗体，我创建了一个
#resultDIV。 - 在Ajax响应将显示在这个DIV来。
- Check if the var_PHP_data var is set (in PHP, on the server).
- If yes, just send a blank text response containing that data.
- If no, then draw the form and everything else.
- In the form, I've created a
#resultdiv. - Ajax response will be shown in this div.
另外，还要确保你在本地主机托管的脚本，它被称为test.php的。为了确保这是有弹性的，可以改变的Ajax网址
＆LT;？PHP的echo $ _ SERVER ['PHP_SELF'];？> ，以确保你会击中正确的脚本
Also make sure that you host the script at localhost and that it is called test.php. To make sure this is resilient, you can change the Ajax URL to
<?php echo $_SERVER['PHP_SELF'];?> to make sure that you'll hit the correct script.
<?php
if (isset($_GET['var_PHP_data'])) {
echo $_GET['var_PHP_data'];
} else {
?>
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js">
<script>
$(document).ready(function() {
$('#sub').click(function() {
var var_data = "Hello World";
$.ajax({
url: 'http://localhost/test.php',
type: 'GET',
data: { var_PHP_data: var_data },
success: function(data) {
// do something;
$('#result').html(data)
}
});
});
});
</script>
</head>
<body>
<input type="submit" value="Submit" id="sub"/>
<div id="result">
</body>
</html>
<?php } ?>
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