将数据框转换为列表 [英] Convert data frame to list
问题描述
我正在尝试从R中的数据帧转到列表结构(而且我从技术上知道数据帧是一个列表)。我有一个包含参考化学品及其机制的数据框架不同的目标。例如,雌激素是雌激素受体激动剂。我想要的是将数据框转换为列表,因为我厌倦了输入如下的东西:
refchem $ chemical_id [refchem $ target ==AR& refchem $ mechanism ==Agonist]
每次我需要访问特定参考化学品列表。我更愿意通过以下方式访问化学品:
refchem $ AR $ Agonist
/ pre>
我正在寻找一个一般的答案,即使我给了一个简化的例子,因为并不是所有的目标都有所有机制。
这是一个非常容易的循环:
example< - data.frame(target = rep(c(t1,t2,t3),each = 20),
mechan = rep(c(m1,m2),each = 10,3),
chems = paste0(chem,1:60))
oneoption< - list()
for(target in unique(example $ target)){
oneoption [[目标]]< - list()
for(mech in unique(example $ mechan)){
oneoption [[target]] [[mech]]< - as.character(example $ chems [example $ target == target& example $ mechan == mech])
}
}
我只是想知道是否有更聪明的方法来做到这一点。我试过玩过
lapply
,没有任何进展。解决方案使用
split
:split(refchem,list(refchem $ target ,refchem $ mechanism))
应该做的伎俩。
新的访问方式将是
refchem $ AR.Agonist
I am trying to go from a data frame to a list structure in R (and I know technically a data frame is a list). I have a data frame containing reference chemicals and their mechanisms different targets. For example, estrogen is an estrogen receptor agonist. What I would like is to transform the data frame to a list, because I am tired of typing out something like:
refchem$chemical_id[refchem$target=="AR" & refchem$mechanism=="Agonist"]
every time I need to access the list of specific reference chemicals. I would much rather access the chemicals by:
refchem$AR$Agonist
I am looking for a general answer, even though I have given a simplified example, because not all targets have all mechanisms.
This is really easy to accomplish with a loop:
example <- data.frame(target=rep(c("t1","t2","t3"),each=20), mechan=rep(c("m1","m2"),each=10,3), chems=paste0("chem",1:60)) oneoption <- list() for(target in unique(example$target)){ oneoption[[target]] <- list() for(mech in unique(example$mechan)){ oneoption[[target]][[mech]] <- as.character(example$chems[ example$target==target & example$mechan==mech ]) } }
I am just wondering if there is a more clever way to do it. I tried playing around with
lapply
and did not make any progress.解决方案Using
split
:split(refchem, list(refchem$target, refchem$mechanism))
Should do the trick.
The new way to access would be
refchem$AR.Agonist
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