在整个数据帧中替换字符串/值 [英] replace string/value in entire dataframe
本文介绍了在整个数据帧中替换字符串/值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有没有这样做?
这是我的数据集的一个例子
数据
resp ABC
0 1可怜的穷人
1 2好可怜
2 3非常好非常好
3 4坏的坏坏
4 5非常糟糕非常糟糕非常糟糕
5 6差不好很糟糕
6 7好好好
7 8非常好非常好非常好
8 9坏坏坏
9 10非常糟糕非常糟糕非常糟糕
所需结果:
数据
resp ABC
0 1 3 3 4
1 2 4 3 4
2 3 5 5 5
3 4 2 3 2
4 5 1 1 1
5 6 3 4 1
6 7 4 4 4
7 8 5 5 5
8 9 2 2 1
9 10 1 1 1
非常糟糕= 1,ba d = 2,差= 3,好= 4,非常好= 5
// Jonas
解决方案
使用替换一个>
在[126]中:df.replace(['very bad','bad','poor','好,'很好'],
[1,2,3,4,5])
输出[126]:
resp ABC
0 1 3 3 4
1 2 4 3 4
2 3 5 5 5
3 4 2 3 2
4 5 1 1 1
5 6 3 4 1
6 7 4 4 4
7 8 5 5 5
8 9 2 2 1
9 10 1 1 1
I have a very large dataset were I want to replace strings with numbers. I would like to operate on the dataset without typing a mapping function for each key (column) in the dataset. (similar to the fillna method, but replace specific string with assosiated value). Is there anyway to do this?
Here is an example of my dataset
data
resp A B C
0 1 poor poor good
1 2 good poor good
2 3 very good very good very good
3 4 bad poor bad
4 5 very bad very bad very bad
5 6 poor good very bad
6 7 good good good
7 8 very good very good very good
8 9 bad bad very bad
9 10 very bad very bad very bad
The desired result:
data
resp A B C
0 1 3 3 4
1 2 4 3 4
2 3 5 5 5
3 4 2 3 2
4 5 1 1 1
5 6 3 4 1
6 7 4 4 4
7 8 5 5 5
8 9 2 2 1
9 10 1 1 1
very bad=1, bad=2, poor=3, good=4, very good=5
//Jonas
解决方案
Use replace
In [126]: df.replace(['very bad', 'bad', 'poor', 'good', 'very good'],
[1, 2, 3, 4, 5])
Out[126]:
resp A B C
0 1 3 3 4
1 2 4 3 4
2 3 5 5 5
3 4 2 3 2
4 5 1 1 1
5 6 3 4 1
6 7 4 4 4
7 8 5 5 5
8 9 2 2 1
9 10 1 1 1
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