C中的LinkedList Struct Typedef [英] LinkedList Struct Typedef in C

问题描述

  typedef我想尝试在C中构建一个基本的链接列表。 struct 
 {
 char letter; 
 int number; 
 list_t * next; 
} list_t; 
 
 char letters [] = {ABCDEFGH}; 
 
 list_t openGame，ruyLopez; 
 openGame.letter = letters [4]; 
 openGame.number = 4; 
 openGame.next =& ruyLopez; 
 
 
 ruyLopez.letter = letters [5]; 
 ruyLopez.number = 4; 
 ruyLopez.next = NULL; 
  

它不会接受我在struct中的定义：

  list_t * next; 
  

由于同样的原因，它不会接受：

  openGame.next =& ruyLopez; 
  

解决方案

当您使用 list_t在你的代码中，下一个，编译器不知道如何处理 list_t ，因为你还没有声明。尝试这样：

  typedef struct list {
 char letter; 
 int number; 
 struct list * next; 
}列表; 
  

正如H2CO3在评论中指出的，使用 _t 作为标识符后缀不是一个好主意，所以不要使用 list_t 。

I am try to build a basic linked list in C. I seem to get an error for this code:

typedef struct
{
    char letter;
    int number;
    list_t *next;
}list_t;

char letters[] = {"ABCDEFGH"};

list_t openGame, ruyLopez;
openGame.letter = letters[4];
openGame.number = 4;
openGame.next = &ruyLopez;


ruyLopez.letter = letters[5];
ruyLopez.number = 4;
ruyLopez.next = NULL;

It won't accept my definition in the struct:

list_t *next;

And for the same reason it won't accept:

openGame.next = &ruyLopez;

解决方案

When you are using list_t *next in your code, the compiler doesn't know what to do with list_t, as you haven't declared it yet. Try this:

typedef struct list {
    char letter;
    int number;
    struct list *next;
} list;

As H2CO3 pointed out in the comments, using _t as an identifier suffix is not a great idea, so don't use list_t.

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