如何使用ksh（或另一个shell脚本）获得现在和不同日期（分钟）之间的区别？ [英] How to get the difference between now and a different date (in minutes) using ksh (or another shell script)?

问题描述

使用以下值给出两个变量：

Giving two variables with the followind values:

date1 = Mon Feb 27 16:21:34 WET 2012
date2 = Mon Feb 27 16:29:34 WET 2012

如何使差异分钟）使用ksh？

How can I make the difference (in minutes) between them using ksh?

我正在使用Solaris 10。

我做了你所说的，这是错误：

$ function d { echo $((($(date -d"$2" +%s)-$(date -d"$1" +%s))/60)); }
$ d "Mon Feb 27 16:21:34 WET 2012" "Mon Feb 27 16:29:34 WET 2012"
date: illegal option -- d
date: illegal option -- M
date: illegal option -- o
date: illegal option -- n
date: illegal option --
date: illegal option -- F
date: illegal option -- e
date: illegal option -- b
date: illegal option --
date: illegal option -- 2
date: illegal option -- 7
date: illegal option --
date: illegal option -- 1
date: illegal option -- 6
date: illegal option -- :
date: illegal option -- 2
date: illegal option -- 9
date: illegal option -- :
date: illegal option -- 3
date: illegal option -- 4
date: illegal option --
date: illegal option -- W
date: illegal option -- E
date: illegal option -- T
date: illegal option --
date: illegal option -- 2
date: illegal option -- 0
date: illegal option -- 1
date: illegal option -- 2
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]
date: illegal option -- d
date: illegal option -- M
date: illegal option -- o
date: illegal option -- n
date: illegal option --
date: illegal option -- F
date: illegal option -- e
date: illegal option -- b
date: illegal option --
date: illegal option -- 2
date: illegal option -- 7
date: illegal option --
date: illegal option -- 1
date: illegal option -- 6
date: illegal option -- :
date: illegal option -- 2
date: illegal option -- 1
date: illegal option -- :
date: illegal option -- 3
date: illegal option -- 4
date: illegal option --
date: illegal option -- W
date: illegal option -- E
date: illegal option -- T
date: illegal option --
date: illegal option -- 2
date: illegal option -- 0
date: illegal option -- 1
date: illegal option -- 2
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]
0
$

推荐答案

好的，这是一个C程序，可能会工作。它是（轻轻地）在solaris上测试。

well, here's a C program that might work. it's (lightly) tested on solaris.

它使用POSIX标准 strptime（3）功能来解析给定的字符串，并在epoch秒内打印结果。

it uses the POSIX standard strptime(3) function to parse a given string and prints the result in epoch seconds.

在理论上应该是是

$ ./strptime "Mon Feb 27 16:21:34 WET 2012" "%a %b %e %H:%M:%S %Z %Y"

但我还没有得到识别WET时区，所以你可能需要把它放在一个字面上：

but i haven't been able to get it to recognize the "WET" timezone, so you may need to just put that in as a literal:

$ ./strptime "Mon Feb 27 16:21:34 WET 2012" "%a %b %e %H:%M:%S WET %Y"
1330377694

这里是代码：

#define _GNU_SOURCE

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <errno.h>
#include <time.h>

#define ARGS 3
#define USAGE printf("Usage: %s string format\n",argv[0]);
#define EARGS { printf("%s: %s arguments (%d)\n",argv[0],argc<ARGS?"Insufficient":"Too many",argc-1); USAGE; exit(2); }

#define err(_s,_p,_f) {fprintf(stderr,"%s: %s: %s\n",(_p),(_f),strerror(errno));exit(_s);}

int main(int argc,char**argv){
        struct tm tm;
        time_t t;

        if(argc!=ARGS)EARGS;

        strptime(argv[1],argv[2],&tm);
        if(-1==(t=mktime(&tm)))err(1,argv[0],"mktime");
        if(0>printf("%lld\n",(long long)t))err(1,argv[0],"printf");
        return 0;
}

按照

$ CFLAGS='-W -Wall -Wshadow -std=gnu99' make strptime

（可能需要gcc，不知道sun cc是否在这里工作）

(probably requires gcc, no idea if sun cc will work here)

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