Python datetime和utc offset转换忽略时区/夏令时 [英] Python datetime and utc offset conversion ignoring timezone/daylight savings

问题描述

我有两个我想执行的操作，一个是另外一个。

1. 我在UTC上有一个UNIX时间戳，例如1425508527.从这里我想要获得年，月，天等。给定UTC偏移。例如。年份/月/日/时间（UTC -6小时）是多少？答案是2015年3月4日16:35:27。没有提供偏移量（或零点偏移量），答案应为2015年3月4日22:35:27。




2. 现在我在某个位置有日期，以及UTC偏移量。例如2015年3月4日16:35:27和偏移量（UTC -6小时）。我应该得到的UNIX UTC时间戳应该是1425508527.

我能够几乎做2.（使用python datetime库）这样：

  import datetime.datetime as datetime 
 import time 
 import dateutil.tz as tz 
 
 utc_offset = 6 
 time.mktime（datetime（2015,3,4,16,35,27，
 tzinfo = tz.tzoffset （无，utc_offset * 60 * 60））。utctimetuple（））
＃=> 1425486927 
  

上面的问题是utc_offset必须给错误的符号。根据此地图，utc_offset应设置为-6。我没有运气。我不需要/想要处理时区信息，如夏令时。如何在Python中实现？

解决方案

如果您的系统使用 Unix时间，其中
不计算闰秒，则转换可以如下完成：

第1部分：时间戳和偏移到本地日期

 导入datetime作为DT 
导入日历
 
 timestamp = 1425508527 
 offset = -6 
 
 date = DT.datetime（1970,1,1）+ DT.timedelta（seconds = timestamp）
 print （日期）
＃2015-03-04 22:35:27 
 
 localdate = date + DT.timedelta（hours = offset）
 print（localdate）
 ＃2015-03-04 16:35:27 
  

第2部分：本地日期和偏移量到时间戳

  utcdate = localdate  -  DT.timedelta（hours = offset）
 assert date == utcdate 
 
 timetuple = utcdate.utctimetuple（）
 timestamp2 = calendar.timegm（timetuple）
 print（timestamp2）
＃1425508527 
 asser t timestamp == timestamp2 
  

I have two operations I want to perform, one the inverse of the other.

1. I have a UNIX timestamp at UTC, say for instance, 1425508527. From this I want to get the year, month, day etc. given a UTC offset. EG. what is the year/month/day/time in (UTC -6 hours)? The answer is March 4, 2015 at 16:35:27. Without providing an offset (or offset zero) the answer should be March 4, 2015 at 22:35:27.

2. Now I have the date at some location, along with the UTC offset. For instance March 4, 2015 at 16:35:27 and the offset (UTC -6 hours). The UNIX UTC timestamp I should get should be 1425508527.

I am able to almost do 2. (using python datetime library) like this:

import datetime.datetime as datetime
import time
import dateutil.tz as tz

utc_offset = 6
time.mktime(datetime(2015,3,4,16,35,27,
                     tzinfo=tz.tzoffset(None, utc_offset*60*60)).utctimetuple())
# => 1425486927

The problem with the above is that utc_offset has to be given the wrong sign. According to this map, utc_offset should be set to -6. Number 1. I've had no luck with. I don't need/want to deal with timezone information like daylight savings time. How do I implement this in Python?

解决方案

If your system uses Unix time, which does not count leap seconds, then the conversion can be done as follows:

Part 1: timestamp and offset to local date

import datetime as DT
import calendar

timestamp = 1425508527
offset = -6

date = DT.datetime(1970,1,1) + DT.timedelta(seconds=timestamp)
print(date)
# 2015-03-04 22:35:27

localdate = date + DT.timedelta(hours=offset)
print(localdate)
# 2015-03-04 16:35:27

Part 2: local date and offset to timestamp

utcdate = localdate - DT.timedelta(hours=offset)
assert date == utcdate

timetuple = utcdate.utctimetuple()
timestamp2 = calendar.timegm(timetuple)
print(timestamp2)
# 1425508527
assert timestamp == timestamp2

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