Ruby按日期计算项目 [英] Ruby count items by date
本文介绍了Ruby按日期计算项目的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
Fri Jan 28 10:13:19 UTC 2011
Thu Jan 27 16:57:59 UTC 2011
Thu Jan 27 16:41:21 UTC 2011
Wed Jan 26 09:20:48 UTC 2011
Mon Jan 24 16:19:48 UTC 2011
Fri Jan 21 11:45 :34 UTC 2011
Fri Jan 21 11:42:19 UTC 2011
将它们分组,使得输出与每天的项目数量一样为哈希:
Friday 28 => 1
星期四27 => 2
星期三26 => 1
星期一24 => 1
星期五21 => 2
解决方案
或者,将kurumi的解决方案更详细地使用, Jimmy的strftime:
histogram = dates.inject(Hash.new(0))do | hist,date |
hist [date.strftime('%A%d')] + = 1
hist
end.sort_by {| date,count | date.split('').last} .reverse
给我们:
星期五28:1
星期四27:2
星期三26:1
星期一24:1
星期五21:2
确定?
I have an array of dates e.g.
Fri Jan 28 10:13:19 UTC 2011
Thu Jan 27 16:57:59 UTC 2011
Thu Jan 27 16:41:21 UTC 2011
Wed Jan 26 09:20:48 UTC 2011
Mon Jan 24 16:19:48 UTC 2011
Fri Jan 21 11:45:34 UTC 2011
Fri Jan 21 11:42:19 UTC 2011
How can I group them so the output is as hash with the count of items each day:
Friday 28 => 1
Thursday 27 => 2
Wednesday 26 => 1
Monday 24 => 1
Friday 21 => 2
解决方案
Or, to put kurumi's solution more verbosely and using Jimmy's strftime:
histogram = dates.inject(Hash.new(0)) do |hist, date|
hist[date.strftime('%A %d')] += 1
hist
end.sort_by{|date, count| date.split(' ').last}.reverse
give us:
Friday 28: 1
Thursday 27: 2
Wednesday 26: 1
Monday 24: 1
Friday 21: 2
OK?
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