计算按日期和小时分组的行数 [英] Counting number of rows grouped by date and hour
本文介绍了计算按日期和小时分组的行数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
DoorID DateTimeStamp EntryType
1 2013-09-02 09:01:16.000 IN
1 2013-09-02 09:04:09.000 IN
1 2013-09-02 10:19:29.000 IN
1 2013-09-02 10:19:30.000 IN
1 2013-09-02 10:19:32.000 OUT
1 2013-09-02 10:26:36.000 IN
1 2013-09-02 10:26:40.000 OUT
我不想将 OUT
行,只是 IN
。
我相信它需要按照日期
和 DoorID
分组,然后获得小时总数。
$
日期DoorID HourOfDay TotalInPersons
2013-b $ b 我希望它能像这样出来。
09-02 1 0 0
2013-09-02 1 1 0
2013-09-02 1 2 0
2013-09-02 1 3 0
2013-09-02 1 4 0
2013-09-02 1 5 0
2013-09-02 1 6 0
2013-09-02 1 7 0
2013-09-02 1 8 0
2013-09-02 1 9 2
2013-09-02 1 10 3
2013-09-02 1 11 0
2013-09-02 1 12 0
2013-09-02 1 13 0
2013-09-02 1 14 0
2013-09-02 1 15 0
2013-09-02 1 16 0
2013-09-02 1 17 0
2013-09-02 1 18 0
2013- 09-02 1 19 0
2013-09-02 1 20 0
2013-09-02 1 21 0
2013-09-02 1 22 0
2013-09- 02 1 23 0
解决方案
SELECT
[Date] = CONVERT(DATE,DateTimeStamp),
DoorID,
HourOfDay = DATEPART(HOUR,DateTimeStamp),
Tota lInPersons = COUNT(*)
FROM dbo.tablename
WHERE EntryType ='IN'
GROUP BY
CONVERT(DATE,DateTimeStamp),
DoorID,
DATEPART(HOUR,DateTimeStamp)
ORDER BY
[Date],DoorID,HourOfDay;
当然,如果你需要所有的时间,即使没有行代表,这里有一个解决方案将任何一天的输出限制为当天至少有一个 IN
条目的门):
; WITH h AS
(
SELECT TOP(24)h =数字FROM Master..spt_values
WHERE type = N'P'ORDER BY number
$
$ b SELECT
d。[Date],
d.DoorID,
HourOfDay = hh,
TotalInPersons = COUNT(t.EntryType)
FROM doors AS d CROSS JOIN h
LEFT OUTER JOIN dbo.tablename AS t
ON CONVERT(DATE,t.DateTimeStamp)= d。[Date]
AND t.DoorID = d.DoorID
AND DATEPART(HOUR,t.DateTimeStamp)= hh
AND t.EntryType ='IN'
GROUP BY d。[Date],d.DoorID,hh
ORDER BY d。[日期],d.DoorID,hh;
I am tracking customer store entry data in Microsoft SQL Server 2008 R2 that looks something like this:
DoorID DateTimeStamp EntryType
1 2013-09-02 09:01:16.000 IN
1 2013-09-02 09:04:09.000 IN
1 2013-09-02 10:19:29.000 IN
1 2013-09-02 10:19:30.000 IN
1 2013-09-02 10:19:32.000 OUT
1 2013-09-02 10:26:36.000 IN
1 2013-09-02 10:26:40.000 OUT
I don't want to count the OUT
rows, just IN
.
I believe that it needs to be grouped on Date
, and DoorID
, then get the hours totals.
I would like it to come out like this.
Date DoorID HourOfDay TotalInPersons
2013-09-02 1 0 0
2013-09-02 1 1 0
2013-09-02 1 2 0
2013-09-02 1 3 0
2013-09-02 1 4 0
2013-09-02 1 5 0
2013-09-02 1 6 0
2013-09-02 1 7 0
2013-09-02 1 8 0
2013-09-02 1 9 2
2013-09-02 1 10 3
2013-09-02 1 11 0
2013-09-02 1 12 0
2013-09-02 1 13 0
2013-09-02 1 14 0
2013-09-02 1 15 0
2013-09-02 1 16 0
2013-09-02 1 17 0
2013-09-02 1 18 0
2013-09-02 1 19 0
2013-09-02 1 20 0
2013-09-02 1 21 0
2013-09-02 1 22 0
2013-09-02 1 23 0
解决方案
SELECT
[Date] = CONVERT(DATE, DateTimeStamp),
DoorID,
HourOfDay = DATEPART(HOUR, DateTimeStamp),
TotalInPersons = COUNT(*)
FROM dbo.tablename
WHERE EntryType = 'IN'
GROUP BY
CONVERT(DATE, DateTimeStamp),
DoorID,
DATEPART(HOUR, DateTimeStamp)
ORDER BY
[Date], DoorID, HourOfDay;
Of course if you need all hours, even where no rows are represented, here is one solution (which limits the output for any day only to the doors that have at least one IN
entry on that day):
;WITH h AS
(
SELECT TOP (24) h = number FROM Master..spt_values
WHERE type = N'P' ORDER BY number
),
doors AS
(
SELECT DISTINCT DoorID, [Date] = CONVERT(DATE,DateTimeStamp)
FROM dbo.tablename WHERE EntryType = 'IN'
)
SELECT
d.[Date],
d.DoorID,
HourOfDay = h.h,
TotalInPersons = COUNT(t.EntryType)
FROM doors AS d CROSS JOIN h
LEFT OUTER JOIN dbo.tablename AS t
ON CONVERT(DATE, t.DateTimeStamp) = d.[Date]
AND t.DoorID = d.DoorID
AND DATEPART(HOUR, t.DateTimeStamp) = h.h
AND t.EntryType = 'IN'
GROUP BY d.[Date], d.DoorID, h.h
ORDER BY d.[Date], d.DoorID, h.h;
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