在Python中添加N秒到datetime.time的标准方法是什么? [英] What is the standard way to add N seconds to datetime.time in Python?
问题描述
datetime.time
值,是否有一个标准的方法来添加一个整数秒,以便 11: 34:59
+ 3 = 11:35:02
,例如? 这些明显的想法不起作用:
>>> datetime.time(11,34,59)+ 3
TypeError:不支持的+:'datetime.time'和'int'的操作数类型
>>> datetime.time(11,34,59)+ datetime.timedelta(0,3)
TypeError:不支持的+:'datetime.time'和'datetime.timedelta'的操作数类型
> ;>> datetime.time(11,34,59)+ datetime.time(0,0,3)
TypeError:不支持的操作数类型为+:'datetime.time'和'datetime.time'
最后我有这样的书面功能:
def add_secs_to_time(timeval,secs_to_add):
secs = timeval.hour * 3600 + timeval.minute * 60 + timeval.second
secs + = secs_to_add
return datetime.time(secs // 3600,(secs%3600)// 60,secs%60)
相关
我不禁想到我错过了一个更简单的方法
您可以使用 datetime
变量与 timedelta
,并提供一个虚拟日期,然后使用 time
来获取时间值。
例如:
import datetime
a = datetime.datetime 100,1,1,11,34,59)
b = a + datetime.timedelta(0,3)#天,秒,然后是其他字段。
打印a.time()
打印b.time()
结果在两个值中,相隔三秒:
11:34:59
11:35:02
您还可以选择更可读的
b = a + datetime.timedelta(seconds = 3)
if你是如此倾向。
如果你有一个功能可以做到这一点,你可以研究使用 addSecs
以下:
import datetime
def addSecs(tm,secs):
fulldate = datetime.datetime(100,1,1,tm.hour,tm.minute,tm.second)
fulldate = fulldate + datetime.timedelta(seconds = secs )
return fulldate.time()
a = datetime.datetime.now()。time()
b = addSecs(a,300)
打印
print b
输出:
09:11:55.775695
09:16:55
Given a datetime.time
value in Python, is there a standard way to add an integer number of seconds to it, so that 11:34:59
+ 3 = 11:35:02
, for example?
These obvious ideas don't work:
>>> datetime.time(11, 34, 59) + 3
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'int'
>>> datetime.time(11, 34, 59) + datetime.timedelta(0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.timedelta'
>>> datetime.time(11, 34, 59) + datetime.time(0, 0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.time'
In the end I have written functions like this:
def add_secs_to_time(timeval, secs_to_add):
secs = timeval.hour * 3600 + timeval.minute * 60 + timeval.second
secs += secs_to_add
return datetime.time(secs // 3600, (secs % 3600) // 60, secs % 60)
I can't help thinking that I'm missing an easier way to do this though.
Related
You can use full datetime
variables with timedelta
, and by providing a dummy date then using time
to just get the time value.
For example:
import datetime
a = datetime.datetime(100,1,1,11,34,59)
b = a + datetime.timedelta(0,3) # days, seconds, then other fields.
print a.time()
print b.time()
results in the two values, three seconds apart:
11:34:59
11:35:02
You could also opt for the more readable
b = a + datetime.timedelta(seconds=3)
if you're so inclined.
If you're after a function that can do this, you can look into using addSecs
below:
import datetime
def addSecs(tm, secs):
fulldate = datetime.datetime(100, 1, 1, tm.hour, tm.minute, tm.second)
fulldate = fulldate + datetime.timedelta(seconds=secs)
return fulldate.time()
a = datetime.datetime.now().time()
b = addSecs(a, 300)
print a
print b
This outputs:
09:11:55.775695
09:16:55
这篇关于在Python中添加N秒到datetime.time的标准方法是什么?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!