DateTime :: diff()不受时区影响,但始终返回相同的值 [英] DateTime::diff() isn't affected by timezone but always return same value
问题描述
用户的时区是:`美国/丹佛`
拍卖开始时间是:星期四,2012年6月21日03:46:22 AM
拍卖期:1天。
拍卖结束时间:Fri,22 Jun 2012 03:46:22 AM
我存储所有这些信息,因为它在我的数据库(即,所有存储时间基于用户的时区)。
现在我想要实际的结束时间和当前时间之间的差异(美国/丹佛时区)。
我使用了 DateTime()
功能
所以即使我不转换时区;它返回相同的差异(也是错误的)。
我的PHP代码在下面;您还可以在 CodePad 找到它
$ end_time ='Fri,22 Jun 2012 03:46:22 AM';
$ tz ='美国/丹佛';
dateDifference($ end_time,$ tz);
函数dateDifference($ end,$ tz = NULL)
{
$ owner_tz = new DateTimeZone($ tz);
// var_dump($ owner_tz-> getName());
$ from = new DateTime(now,new DateTimeZone('GMT'));
$ from - > setTimeZone($ owner_tz);
$ to = new DateTime($ end,new DateTimeZone('GMT'));
/ * @注意:我已经评论过setTimeZone(),因为我已经存储
*`end time`根据用户的时区,所以我不需要再次转换
*到用户的时区。您可以在线下方发表评论。
*它不会影响结果。
* /
// $ to - > setTimeZone($ owner_tz);
//使用date_diff()的程序样式
$ interval = date_diff($ from,$ to);
var_dump($ interval);
//使用dateTime :: diff()的OO样式
$ interval = $ from-> diff($ to);
var_dump($ interval);
}
返回:
object(DateInterval)[4]
public'y'=> int 0
public'm'=> int 0
public'd'=> int 0
public'h'=> int 16
public'i'=> int 40
public's'=> int 24
public'invert'=> int 0
public'days'=> int 6015
参考文献:
我有解决方案,所以我想分享
实际上,我已经在 config.inc.php
文件中设置默认时区,如下
date_default_timezone_set('America / Los_Angeles');
然后我查看当前时间和时间来自phpmyadmin的MySQL服务器区域
SELECT NOW(),SYSDATE(),@@ global。 time_zone,@@ session.time_zone,
TIMEDIFF(NOW(),CONVERT_TZ(NOW(),@@ session.time_zone,'+00:00'))
AS OFFSET
返回 OFFSET
值 +05:30
解决方案步骤:
-
首先我更改了时区的mySQL服务器到格林尼治标准时间UTC / UTC +00:00 (MySQL服务器上的超级权限)
SET GLOBAL time_zone ='+00:00';
- 我们使用
start_date = NOW()$保存日期和时间c $ c>(列数据类型:
DATETIME
)
现在有2第一种方法(使用PHP America / Denver )
href =http://php.net/manual/en/book.datetime.php =nofollow> DateTime )
/ *
*首先将时区设置为GMT。
*这是必须的,因为默认时区不同于用户时区
* /
$ gmt = new DateTimeZone('GMT');
$ user_tz ='美国/丹佛';
$ st = new DateTime($ row [`start_date`],$ gmt);
//现在设置用户时区
$ st-> setTimezone($ user_tz);
$ stime = $ qt-> format('r');
echo $ stime;
第二种方法(使用MySQL UNIX_TIMESTAMP )
#$从时间戳中从服务器检索数据
$ qry =SELECT`start_date`,UNIX_TIMESTAMP(`start_date`)AS sTimestamp FROM ...
$ st = new DateTime ('@'。$ row ['sTimestamp']);
$ stime = $ st-> format('r');
echo $ stime;
注意:不要更改 start_date
以 strtotime()
为时间戳。它将从返回不同的值UNIX_TIMESTAMP()
ie
strtotime($ row ['start_date'])!== $ row ['sTimestamp']
I am adding auction-based data to my system. For example:
user's timezone is : `America/Denver`
auction start time is : Thu, 21 Jun 2012 03:46:22 AM
auction period : 1 day.
auction end time : Fri, 22 Jun 2012 03:46:22 AM
I store all these information as it is in my DB (i.e. all stored time based on user's timezone).
Now I want the actual difference between end time and current time (of America/Denver timezone).
I used DateTime()
functions
so even I don't convert the timezone; it returns same difference (and that is wrong too).
My PHP code is below; you can also find it at CodePad
$end_time = 'Fri, 22 Jun 2012 03:46:22 AM';
$tz = 'America/Denver';
dateDifference($end_time,$tz);
function dateDifference($end, $tz = NULL)
{
$owner_tz = new DateTimeZone($tz);
//var_dump($owner_tz->getName());
$from = new DateTime("now", new DateTimeZone('GMT'));
$from ->setTimeZone($owner_tz);
$to = new DateTime($end,new DateTimeZone('GMT'));
/* @Note:I have commented below setTimeZone() because I have already stored
* `end time` as per user's timezone, So I dont need to convert it again
* into user's timezone.you can un-comment below line.
* it doesn't affect the results anyways.
*/
//$to ->setTimeZone($owner_tz);
//procedural style using date_diff()
$interval = date_diff($from, $to);
var_dump($interval);
// OO style using dateTime::diff()
$interval = $from->diff($to);
var_dump($interval);
}
Returns:
object(DateInterval)[4]
public 'y' => int 0
public 'm' => int 0
public 'd' => int 0
public 'h' => int 16
public 'i' => int 40
public 's' => int 24
public 'invert' => int 0
public 'days' => int 6015
References:
I got the solution, so i would like to share
Actually I have set default timezone in config.inc.php
file as below
date_default_timezone_set('America/Los_Angeles');
then I check the current time and timezone of MySQL server from phpmyadmin with below query
SELECT NOW(), SYSDATE(), @@global.time_zone , @@session.time_zone ,
TIMEDIFF( NOW( ) , CONVERT_TZ( NOW( ) , @@session.time_zone , '+00:00' ))
AS OFFSET
This return the OFFSET
value +05:30
solution steps:
First I changed the timezone of mySQL Server to GMT/UTC +00:00 ( I have super privilage on mySQL server)
SET GLOBAL time_zone = '+00:00';
- We save the date and time using
start_date = NOW()
( column datatype:DATETIME
)
Now there is 2 way to get date and time as per user's timezone (America/Denver
)
first method ( using PHP DateTime)
/*
* first set timezone as GMT.
* This is MUST because default timezone is differ from user timezone
*/
$gmt = new DateTimeZone('GMT');
$user_tz = 'America/Denver';
$st = new DateTime($row[`start_date`], $gmt);
// now set user timezone
$st->setTimezone($user_tz );
$stime = $qt->format('r');
echo $stime;
second method (using MySQL UNIX_TIMESTAMP)
#$retrieve data from server in timestamp
$qry = "SELECT `start_date`,UNIX_TIMESTAMP(`start_date`) AS sTimestamp FROM..."
$st = new DateTime('@'.$row['sTimestamp ']);
$stime = $st->format('r');
echo $stime;
Note : dont change start_date
to timestamp with strtotime()
. It will return different value from the UNIX_TIMESTAMP()
i.e.
strtotime($row['start_date']) !== $row['sTimestamp']
这篇关于DateTime :: diff()不受时区影响,但始终返回相同的值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!