PHP Symfony2添加60年到两天的Datetime对象的一个​​人 [英] PHP Symfony2 add 60 years to the both day Datetime object of a person

问题描述

我需要在个人/工作人员的出生日期添加60年，这个人被存储在数据库中，我有以下代码来定义这个人加上getter和setter：

I need to add 60 Years to the date of birth of a person/worker, this person is stored in the database and I have the following code to define this person plus the getters and setters:

/**
 * @ORM\Entity
 * @ORM\Table(name="Worker")
 * @ORM\Entity(repositoryClass="Osd\RetireBundle\Entity\WorkerRepository")
 */
class Worker
{
/**
 * @ORM\Id
 * @ORM\Column(type="integer")
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $idWorker;

/**
 * @ORM\Column(type="string", length=20)
 */
private $omang;

/**
 * @ORM\Column(type="string", length=100)
 */
private $workerTitle;


/**
 * @ORM\Column(type="string", length=100)
 */
private $workerName;

/**
 * @ORM\Column(type="string", length=100)
 */
private $workerSurname;

/**
 * @ORM\Column(type="date")
 */
private $birthDay;

/**
 * @ORM\Column(type="date")
 */
private $dateOfEmployment;

在这个人/工作者里面，我真的不知道在这里做的是正确的，但是我试图创建一个这样的方法：

Inside this person/Worker, I do not really know is is correct to do it there, but I was trying to create a method like this:

    public function getRetireDate (){
   if($this->getBirthDay()) 
       return $retireYear = $this->getBirthDay()->add(new DateInterval('P60Y'));
}

我真的不知道在哪里添加方法，但现在是在工人（Im新到symfony）。但是当我打电话给它时，它会给我这个错误：

I dont really know where to add the method?, but for now is inside the worker (Im new to symfony). but when ever I call it it gives me this error:

FatalErrorException: Error: Class 'Osd\RetireBundle\Entity\DateInterval' not found in /var/www/Org/src/Osd/RetireBundle/Entity/Worker.php line 202

谁做过或知道如何和在哪里实现这个功能的人？
提前感谢你。

Any one who has done or knows how and where to achieve this feature? Regards and thank you in advance.

推荐答案

我想我已经解决了问题，你的答案@david真的很有帮助;现在我的方法看起来像这样：

I think I have sorted out the problem and your answer @david was really helpful; now my method looks like this:

public function getRetireYear (){
       return $this->retireYear = $this->getBirthDay()->add(new \DateInterval('P60Y'));
}

我在工作中有一个私有的var称为$ retireYear。而已。它奇妙地工作
谢谢。

and I have a private var inside the Worker called $retireYear. that's it. It works wonderfully. Thank you.

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